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Wewaii [24]
2 years ago
8

A 2kg book is held against a vertical wall. The coefficient of friction is 0.45. What is the minimum force that must be applied

on the book, perpendicular to the wall, to prevent the book from slipping down the wal
Physics
1 answer:
Vika [28.1K]2 years ago
8 0

We have that for the Question "A 2kg book is held against a vertical wall. The <em>coefficient </em>of friction is 0.45. What is the minimum force that must be applied on the <em>book</em>, perpendicular to the wall, to prevent the book from slipping down the wal" it can be said that  the minimum force that must be applied on the <em>book is</em>

  • F=44N

From the question we are told

A 2kg book is held against a vertical wall. The <em>coefficient </em>of friction is 0.45. What is the minimum force that must be applied on the <em>book</em>, perpendicular to the wall, to prevent the book from slipping down the wal

Generally the equation for the  Force  is mathematically given as

F=\frac{mg}{\mu}\\\\F=\frac{2*9.8}{0.45}\\\\

F=44N

Therefore

the minimum force that must be applied on the <em>book is</em>

F=44N

For more information on this visit

brainly.com/question/23379286

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120 =  10Log(\frac{I}{10^{-12}} )\\\\12 =  Log(\frac{I}{10^{-12}} )\\\\10^{12} = \frac{I}{10^{-12}}\\\\I = 10^{12}  * 10^{-12}\\\\I = 10^0\\\\I = 1 \ W/m^2

The intensity of sound of a whisper;

20 =  10Log(\frac{I}{10^{-12}} )\\\\2 =  Log(\frac{I}{10^{-12}} )\\\\10^{2} = \frac{I}{10^{-12}}\\\\I = 10^{2}  * 10^{-12}\\\\I = 10^{-10} \ W/m^2\\\\

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