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Evgesh-ka [11]
3 years ago
10

Find the expression for pressure exerted by fluid with proper description​

Physics
1 answer:
fredd [130]3 years ago
3 0

Explanation:

The pressure exerted by a column of liquid of height h and density ρ is given by the hydrostatic pressure equation p = ρgh, where g is the gravitational acceleration

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If a drop is to be deflected a distance d = 0.350 mm by the time it reaches the end of the deflection plate, what magnitude of c
Sloan [31]

Answer:

q = 4.87 X 10^ -14 C

Explanation:

As d=0.350 mm

The ink drop will be accelerated by the electric field between the plates:

a = F/m

d = a(D0 / v)^2 / 2 ...... 1

a = qE/m ............... 2

Substituting 2  into 1:

d = (qE/m)(D0 / v)^2 / 2

q = 2mdv^2 / [E(D0)^2]

q = 2(1.00e-11 kg)(3.50e-4 m)(15.0 m/s)^2 / [(7.70e4 N/C)(2.05e-2 m)^2]

q = 4.87e-14 C

6 0
3 years ago
Calculate the time required (in years) for water to penetrate a layer of clay that is 40 cm deep when exposed to a hydraulic gra
guapka [62]

Answer:

The time required to penetrate the 40 cm clay layer is 126.82 years

Explanation:

Given:

Hydraulic gradient = 1 \frac{cm}{cm}

Permeability of clay K = 1 \times 10^{-8} \frac{cm}{sec}

Time required to penetrate 40 cm clay layer,

  = \frac{40}{K}

  = \frac{40}{1 \times 10^{-8} }

  = 40 \times 10^{8} sec

But we have to find time in years,

  = \frac{40 \times 10^{8} }{24 \times 60 \times 60 \times 365} years

  = 126.82 years

Therefore, the time required to penetrate the 40 cm clay layer is 126.82 years

5 0
3 years ago
Read 2 more answers
A man has 60w bulbs and a 240w water heater in his apartment. If the bulbs and the water heater are switched on for four hours d
SVETLANKA909090 [29]

Answer: N43.2

Explanation:

Given

Power consumption of bulb and water are 60\ W and 240\ W

If the Devices are on for four hours

Total power of devices 60+240=300\ W

Energy consumed for 4 hours is

\Rightarrow 300\times 4=1200 Wh\\\Rightarrow 1.2\ kWh

For 30 days it is 1.2\times 30=36\ kWh

Cost for 30 days 36\times 1.2=43.2\ N

3 0
3 years ago
Please I need help........
LenKa [72]

Answer:

7.46 J/kg/K

Explanation:

The heat absorbed or lost is:

q = mCΔT

where m is the mass, C is the heat capacity, and ΔT is the change in temperature.

Given q = 15.0 J, m = 0.201 kg, and ΔT = 10.0 °C:

15.0 J = (0.201 kg) C (10.0 °C)

C = 7.46 J/kg/°C

Which is the same as 7.46 J/kg/K.

7 0
3 years ago
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Electric fields are MOST associated with ________.
alukav5142 [94]
With each point in space
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3 years ago
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