Answer:
Δt = 5.29 x 10⁻⁴ s = 0.529 ms
Explanation:
The simple formula of the distance covered in uniform motion can be used to find the interval between when the sound arrives at the right ear and the sound arrives at the left ear.
where,
Δt = required time interval = ?
Δs = distance between ears = 18 cm = 0.18 m
v = speed of sound = 340 m/s
Therefore,
<u>Δt = 5.29 x 10⁻⁴ s = 0.529 ms</u>
Pitch is the sensation of certain frequencies to the ear. High frequency = high pitch, low frequency = low pitch.
f = c(speed of the wave) / <span>λ (wavelength)
1. 343m/s / 0.77955m = 439.99 Hz
This corresponds to pitch A
2. 343m/s / 0.52028m = 659.26 Hz
</span> This corresponds to pitch E
<span>
3. 343m/s / 0.65552m = 523.349 Hz
</span>This corresponds to pitch C
4. using f = c / λ
λ = c / f<span>
= 343m/s / 587.33 = 0.583999 m = 0.584 m
</span>
Answer:I=12 A
Explanation:
Given
Resistance 
Voltage 
According to ohm's law current through a conductor is directly proportional to the voltage applied.
where V=Voltage
I=Current
R=resistance
It's a bit of a trick question, had the same one on my homework. You're given an electric field strength (1*10^5 N/C for mine), a drag force (7.25*10^-11 N) and the critical info is that it's moving with constant velocity(the particle is in equilibrium/not accelerating).
<span>All you need is F=(K*Q1*Q2)/r^2 </span>
<span>Just set F=the drag force and the electric field strength is (K*Q2)/r^2, plugging those values in gives you </span>
<span>(7.25*10^-11 N) = (1*10^5 N/C)*Q1 ---> Q1 = 7.25*10^-16 C </span>
Answer:
it snaps
Explanation:
the more force you put on it, the wired out it gets than it snaps. I think
