Consider the Bose-Einstein distribution: F60 per unit energy can be written as N aE 6.) (20pts) Assuming BE <<1,obtain an
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Answer:
0.615 m
Explanation:
We need to determine the force on the spring first. By Newton's second law of motion, force is the product of the mass and acceleration. The mass is given.
The acceleration is determined using the equation of motion.
Given parameters:
Initial velocity, <em>u</em> = 0.00 m/s
Distance, <em>s</em> = 4.19 m
Time, <em>t</em> = 0.601 s
We use the equation
With <em>u</em> = 0.00 m/s,
The force is
From Hooke's law, the extension, <em>e</em>, of a string is given by
where <em>k</em> is the spring constant.
Hence,