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mash [69]
3 years ago
14

A soft drink contains 63 g of sugar in 378 g of H2O. What is the concentration of sugar in the soft drink in mass percent

Chemistry
1 answer:
Doss [256]3 years ago
3 0

Answer:

\% m/m= 14.3\%

Explanation:

Hello,

In this case, the by mass percent is computed as shown below:

\% m/m=\frac{m_{solute}}{m_{solute}+m_{solvent}} *100\%

Whereas the solute is the sugar and the solvent the water, therefore, the concentration results:

\% m/m=\frac{63g}{63g+378g} *100\%\\\\\% m/m= 14.3\%

Best regards.

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The ratio of the areas of the signals in the h NMR spectrum of pentan-3-ol is 6: 4: 1: 1. The correct option is A.

<h3>What is a NMR spectrum?</h3>

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There are 4 different kinds of signals due of the 4 different environment experienced by these 12 hydrogens.

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