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STALIN [3.7K]
3 years ago
14

What is the concentration of hydrogen ions in a solution of KOH with a pOH of 1.72?

Chemistry
1 answer:
bezimeni [28]3 years ago
3 0

Answer:

[h+]= 5.25e-13

Explanation:

pH= 14-1.72= 12.28

[h+]= 5.25e-13

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A mixture that separates into different layers when you stop stirring it is Select one: a. a solution. b. a suspension. c. a col
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Answer: b suspension

a suspension is a heterogeneous mixture that contains solid particles sufficiently large for sedimentation . The particles may be

visible to the naked eye, usually must be larger than one micrometer , and will eventually settle, although the mixture is only classified as a suspension when and while the particles have not settled out. A suspension is a heterogeneous mixture in which the solute particles do not dissolve , but get suspended throughout the bulk of the solvent , left floating around freely in the medium. [1] The internal phase (solid) is dispersed throughout the external phase (fluid) through mechanical agitation , with the use of certain excipients or suspending agents.

An example of a suspension would be sand in water. The suspended particles are visible under a

microscope and will settle over time if left undisturbed. This distinguishes a suspension from a colloid , in which the suspended particles are smaller and do not settle.

Colloids and suspensions are different from

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8 0
3 years ago
A chemistry student needs to standardize a fresh solution of sodium hydroxide. She carefully weighs out 192.mg of oxalic acid H2
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Answer:

The molarity of the NaOH solution is 0.076 M

Explanation:

Step 1: Data given

Mass of oxalic acid = 192 mg = 0.192 grams

volume = 250 mL = 0.250 L

Molar mass oxalic acid = 90.03 g/mol

Step 2: The balanced equation

H2C2O4 + 2NaOH → Na2C2O4 + H2O

Step 3: Calculate moles of oxalic acid

Moles oxalic acid = 0.192 grams / 90.03 g/mol

Moles oxalic acid = 0.00213 moles

Step 4: Calculate molarity of oxalic acid

Molarity = Moles / volume

Molarity = 0.00213 moles / 0.250 L

Molarity = 0.00852 M

Step 5: Calculate Molarity of NaOH

2 Ca*Va = Cb*Vb

with Ca = Molarity of oxalic acid = 0.00852 M

with Va = volume of oxalic acid = 0.250 L

with Cb = Molarity of NaOH = TO BE DETERMINED

with Vb = volume of 0.0558 L

Cb = (2*0.00852 * 0.25) / 0.0558

Cb = 0.076 M

The molarity of the NaOH solution is 0.076 M

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