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3 years ago

The potential at a point is 20 V. The work done to bring a charge of 0.5 C from infinity to this point will be what?

1 answer:

8 0

1. The problem statement, all variables and given/known data The potential at a point is 20 V. Calculate the work done in bringing a charge of 0.5 C to this point. 2. Relevant equations V = Ee / q W = -Ee 3. The attempt at a solution Ee = 10

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Please help. Possibly more than one answer:

attashe74 [19]

Answer:

air friction

Explanation:

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3 years ago

think of two school rules and briefly describe how these rules help protect health and why its important to follow them.

Softa [21]

Answer:

Wash your hand when you are done using the restroom because you could spread germs if not.

Don't come to school if you are sick because then you will get others sick.

Explanation:

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4 years ago

Read 2 more answers

An earthquake in San Francisco produces a wave with a period of 0.80 seconds and a wavelength of 40 m., How long will it take fo

gtnhenbr [62]

Answer:

A) 3.11 Hrs

Explanation:

Wave speed is given by the formula

$Speed = \frac{wavelength}{Time\: period}$

now we will have

$speed = \frac{40}{0.80}$

$v = 50 m/s$

now the time taken by the wave to move the distance 560 km is given as

$t = \frac{distance}{speed}$

$t = \frac{560\times 10^3}{50}$

$t = 11200 s$

t = 3.11 hours

4 0

3 years ago

7. You start to walk toward the east towards home at a constant speed of 4 km/hr. At the same time, Someone else leaves your hom

amm1812

A) position time graph for both is shown

here one of the graph is of lesser slope which means it is moving with less speed while other have larger slope which shows larger speed

At one point they intersects which is the point where they both will meet

B) Let the two will meet after time "t"

now we can say that

if they both will meet after time "t"

then the total distance moved by you and other person will be same as the distance between you and home

so it is given as

$v_1t + v_2t = d$

$4*t + 28*t = 3.2 km$

$t = \frac{3.2}{32} = 0.1 hr$

so they will meet after t = 6 min

so from position time graph we can see that two will meet after t = 6 min where at this position two graphs will intersect

4 0

4 years ago

A 7.0 kg bowling ball has a moment of inertia of 2.8x10-2 kg m2, and a radius of 0.10 m. If it rolls down the lane at an angular

slega [8]

Hi there!

Angular momentum is equivalent to:

$\large\boxed{L = I\omega}$

L = angular momentum (kgm²/s)

I = moment of inertia (kgm²)

ω = angular velocity (rad/sec)

Plug in the given values for moment of inertia and angular speed:

$L = (0.028)(40) = \boxed{1.12 kgm^2/s}$

8 0

2 years ago