I need help with these two not sure on them
1 answer:
You might be interested in
Answer:
(a). The initial velocity is 28.58m/s
(b). The speed when touching the ground is 33.3m/s.
Explanation:
The equations governing the position of the projectile are
where is the initial velocity.
(a).
When the projectile hits the 50m mark, ; therefore,
solving for we get:
Thus, the projectile must hit the 50m mark in 1.75s, and this condition demands from equation (1) that
which gives
(b).
The horizontal velocity remains unchanged just before the projectile touches the ground because gravity acts only along the vertical direction; therefore,
the vertical component of the velocity is
which gives a speed of
Answer:
Explanation:
Here we will call:
1. : The energy when the first spring is compress
2. : The energy after the mass is liberated by the spring
3. : The energy before the second string catch the mass
4. : The energy when the second sping compressed
so, the law of the conservations of energy says that:
1.
2.
3.
where is the work of the friction.
1. equation 1 is equal to:
where K is the constant of the spring, x is the distance compressed, M is the mass and the velocity, so:
Solving for velocity, we get:
= 65.319 m/s
2. Now, equation 2 is equal to:
where M is the mass, the velocity in the situation 2,
is the velocity in the situation 3,
is the coefficient of the friction, N the normal force and d the distance, so:
Volving for , we get:
3. Finally, equation 3 is equal to:
where is the constant of the second spring and
is the compress of the second spring, so:
solving for , we get: