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iogann1982 [59]
3 years ago
8

A 1250 kg car is stopped at a traffic light. A 3550 kg truck moving at 8.33 m/s hits the car from behind. If bumpers lock, how f

ast will the two vehicles move?
Physics
1 answer:
Radda [10]3 years ago
7 0

Answer:

the two vehicles will be moving at a speed of 6.16  m/s

Explanation:

This is a case of completely inelastic collision, therefore, the conservation of momentum can be written as:

m_1\,v_1+m_2\,v_2=(m_1+m_2)\,v_f

which given the information provided results into:

m_1\,v_1+m_2\,v_2=(m_1+m_2)\,v_f\\(1250)\,(0)+(3550)\,(8.33)=(1250+3550)\,v_f\\29571.5=4800\,v_f\\v_f=6.16\,\,m/s

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What's the value of 1,152 Btu in joules? A. 1,964,445 J B. 2,485,664 J C. 987,875 J D. 1,215,360 J
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Explanation:

Given,  1,152 British thermal units

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4 0
3 years ago
Read 2 more answers
A 10.0-kg box starts at rest and slides 3.5 m down a ramp inclined at an angle of 10° with the horizontal. If there is no fricti
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Answer:

v_f = 3.45 m/s

Explanation:

As we know that box was initially at rest

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so we will have

mg sin\theta L = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2

now we have

m = 10 kg

\theta = 10^0

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so we will have

10(9.81)sin10 \times 3.5 = \frac{1}{2}(10)(v_f^2 - 0)

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so final speed is given as

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6 0
3 years ago
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