Answer:
Aromatic Hydrocarbons
Explanation:
Aromatic (Pleasant Odour) Hydrocarbons are those having pleasant odours.
When the disk of the moon mask the the disk of the sun,it creates a (solar) eclipse.
Answer:
2H₂ + O₂ → 2H₂O
Explanation:
The expression of the equation is given as:
_H₂ + 2O₂ → 2H₂O
Now for expression above,
Reactants Products
H 2 4
O 4 2
to balance the equation, we use 2 moles of hydrogen gas and 1 mole of oxygen gas;
2H₂ + O₂ → 2H₂O
Empirical formula is the simplest ratio of whole numbers of components in a compound
in 100 g of compound
C H O
mass 25.5 g 6.40 g 68.1 g
number of moles 25.5 g/12 g/mol 6.40 g/ 1 g/mol 68.1 g/ 16 g/mol
= 2.13 mol = 6.40 mol = 4.26 mol
divide by least number of moles
2.13/2.13 = 1 6.40/2.13 = 3.0 4.26/2.13 = 2.0
all rounded off
C - 1
H - 3
O - 2
empirical formula - CH₃O₂
Answer:
1.88 × 10²³ particles
Explanation:
Given data:
Volume of H₂ = 0.7 L
Number of particles at STP = ?
Solution:
First of all we will calculate the number of moles of H₂.
PV = nRT
n = PV / RT
n = 1 atm . 7 L / 0.0821 L. atm. mol⁻¹. k⁻¹ × 273.15 K
n = 7 atm. L / 22.43 L. atm. mol⁻¹
n = 0.312 mol
it is known that,
2 g H₂ = 1 mol = 6.022 × 10²³ particles
For 0.312 mol
0.312 × 6.022 × 10²³ particles
1.88 × 10²³ particles
