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aniked [119]
3 years ago
14

Choose all the answers that apply. Which of the following will decrease reaction rate? increase in pressure. decrease temperatur

e. increase concentration. decrease concentration
Chemistry
2 answers:
zloy xaker [14]3 years ago
4 0
Decrease temperature and decrease of concentration will decrease reaction rate, because less molecules will be able to react.
Oksana_A [137]3 years ago
4 0

Answer:

Decrease temperature and decrease of concentration will decrease reaction rate, because less molecules will be able to react.

Explanation:

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Consider the reaction H2(g) + I2(g) Double headed arrow. HI(g) with an equilibrium constant of 46.3 and a reaction quotient of 5
Alika [10]

Answer:

The reaction shifts to the left.

Explanation:

Equilibrium constant (K) = 46.3

Reaction Quotient (Q) = 525

The relationship between Q and K with their implications are given as;

K = Q (No net reaction)

K > Q (Reaction shifts to the right)

K < Q (Reaction shifts to the left)

Since in this question, Q (525) > K (46.3)

The reaction shifts to the left.

5 0
2 years ago
Which one of the following represents the number of units of each substance
netineya [11]

Answer:B

Explanation:Coefficient represents the number of units of each substance.

4 0
2 years ago
What function do mirrors serve in reflecting telescopes????
UkoKoshka [18]
Enlarge image i think
4 0
3 years ago
whg doe sthe transfer of electrons from magnesium to oxygen cause the ions produced to attract eachother
almond37 [142]
Oxygen gains two electrons when it bonds to form a complete outer shell and magnesium loses two electrons when bonding to gain its full outer shell. 

As electrons are negative, the oxygen (which gains electrons) will become negative and the magnesium (which loses electrons) will become positive.

The negative and positive ions will then attract to one another due to the magnetic pull of the positive and negative.
8 0
3 years ago
A student ran the following reaction in the laboratory at 671 K: 2NH3(g) N2(g) + 3H2(g) When she introduced 7.33×10-2 moles of N
vaieri [72.5K]

Answer:

Kc = 8.05x10⁻³

Explanation:

This is the equilibrium:

                 2NH₃(g)   ⇄     N₂(g)     +     3H₂(g)

Initially       0.0733

React         0.0733α          α/2                3/2α

Eq     0.0733 - 0.0733α    α/2                0.103

We introduced 0.0733 moles of ammonia, initially. So in the reaction "α" amount react, as the ratio is 2:1, and 2:3, we can know the moles that formed products.

Now we were told that in equilibrum we have a [H₂] of 0.103, so this data can help us to calculate α.

3/2α = 0.103

α = 0.103 . 2/3 ⇒ 0.0686

So, concentration in equilibrium are

NH₃ = 0.0733 - 0.0733 . 0.0686 = 0.0682

N₂ = 0.0686/2 = 0.0343

So this moles, are in a volume of 1L, so they are molar concentrations.

Let's make Kc expression:

Kc= [N₂] . [H₂]³ / [NH₃]²

Kc = 0.0343 . 0.103³ / 0.0682² = 8.05x10⁻³

3 0
2 years ago
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