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ivanzaharov [21]
3 years ago
15

A force of 100 newtons is applied to a box at an angle of 36º with the horizontal. If the mass of the box is 25 kilograms, what

is the horizontal acceleration of the box?
Physics
1 answer:
Furkat [3]3 years ago
5 0
The horizontal acceleration of the box is 3.24 m/s^2.

First you find the horizontal component of the force via cosine 36 degrees.

Then with cosine 36 find the horizontal force by multiplying it with 100 N.

Then divide the horizontal force by the mass -- 25 kgs.  F = ma
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ou have been called to testify as an expert witness in a trial involving a head-on collision. Car A weighs 660.0 kg and was trav
Montano1993 [528]

Answer:

    vₐ₀ = 29.56 m / s

Explanation:

In this exercise the initial velocity of car A is asked, to solve it we must work in parts

* The first with the conservation of the moment

* the second using energy conservation

let's start with the second part

we must use the relationship between work and kinetic energy

             W = ΔK                             (1)

for this part the mass is

             M = mₐ + m_b

the final velocity is zero, the initial velocity is v

friction force work is

              W = - fr x

the negative sign e because the friction forces always oppose the movement

we write Newton's second law for the y-axis

              N -W = 0

              N = W = Mg

friction forces have the expression

              fr =μ N

              fr = μ M g

we substitute in 1

               -μ M g x = 0 - ½ M v²

             v² = 2 μ g x

let's calculate

              v² = 2  0.750  9.8  6.00

              v = ra 88.5

              v = 9.39 m / s

Now we can work on the conservation of the moment, for this part we define a system formed by the two cars, so that the forces during the collision are internal and therefore the tsunami is preserved.

Initial instant. Before the crash

         p₀ = + mₐ vₐ₀ - m_b v_{bo}

instant fianl. Right after the crash, but the cars are still not moving

         p_f = (mₐ + m_b) v

         p₀ = p_f

         + mₐ vₐ₀ - m_b v_{bo} = (mₐ + m_b) v

           

         mₐ vₐ₀ = (mₐ + m_b) v + m_b v_{bo}

let's reduce to the SI system

          v_{bo} = 64.0 km / h (1000m / 1km) (1h / 3600s) = 17.778 m / s

let's calculate

         660 vₐ₀ = (660 +490) 9.39 + 490 17.778

         vₐ₀ = 19509.72 / 660

         vₐ₀ = 29.56 m / s

we can see that car A goes much faster than vehicle B

5 0
3 years ago
(4%) Problem 9: A mass is connected to a spring and is allowed to move horizontally. The mass is at a position L when the spring
skad [1K]

Answer:

a) Acceleration is zero , c)   Speed ​​is cero

Explanation:

a) the equation that governs the simple harmonic motion is

         x = A cos (wt +φφ)

Where A is the amplitude of the movement, w is the angular velocity and φ the initial phase determined by the initial condition

Body acceleration is

         a = d²x / dt²

Let's look for the derivatives

         dx / dt = - A w sin (wt + φ)

         a = d²x / dt² = - A w² cos (wt + φ)

In the instant when it is not stretched x = 0

As the spring is released at maximum elongation, φ = 0

            0 = A cos wt

            Cos wt = 0         wt = π / 2

Acceleration is valid for this angle

           a = -A w² cos π/2 = 0

Acceleration is zero

b)

c) When the spring is compressed x = A

Speed ​​is

             v = dx / dt

             v = - A w sin wt

We look for time

            A = A cos wt

            cos wt = 1         wt = 0, π

For this time the speedy vouchers

            v = -A w sin 0 = 0

Speed ​​is cero

5 0
3 years ago
Name the type of simple machine: A ramp on the back of a moving van.
Mrac [35]
C) an inclined plane 
6 0
3 years ago
Read 2 more answers
A sample of oxygen gas occupies a volume of 5.0L at 90kPa pressure. What volume will it occupy at 145kPa?
Burka [1]

Answer:

<h3>The answer is option A</h3>

Explanation:

The new volume can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new volume

V_2 =  \frac{P_1V_1}{P_2}  \\

From the question we have

V_2 =  \frac{5 \times 90000}{145000}  =  \frac{450000}{145000}  =  \frac{450}{145}  \\  = 3.103448...

We have the final answer as

<h3>3.10 L</h3>

Hope this helps you

7 0
3 years ago
A student with a mass of 62.0 kg walks up a flight of stairs with a height of 3.40 meters. If it takes him 7.00 seconds to get t
Inessa05 [86]

Answer:

Power generate by generator = 265 W (Approx.)

Explanation:

Given:

Mass of student = 62 kg

Height of stairs = 3.4 meter

Time taken = 7 second

Find:

Power generate by generator

Computation:

Power = Force x [Distance / Time]

Power = [Mass x gravitational acceleration] x [Distance / Time]

Power = [62 x 9.8][3.4/7]

Power = [607.6][3.4/7]

Power = 265.12

Power generate by generator = 265.12

Power generate by generator = 265 W (Approx.)

3 0
2 years ago
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