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Digiron [165]
3 years ago
14

Find the magnitude of acceleration (ft/s^2) a person experiences when he or she is texting and driving 58mph, hits a wall, and c

omes to a complete stop .24 seconds after impact.
Physics
1 answer:
SVEN [57.7K]3 years ago
7 0

Answer:

350 ft/s²

Explanation:

First, convert mph to ft/s.

58 mi/hr × (5280 ft/mi) × (1 hr / 3600 s) = 85.1 ft/s

Given:

v₀ = 85.1 ft/s

v = 0 ft/s

t = 0.24 s

Find: a

v = at + v₀

a = (v − v₀) / t

a = (0 ft/s − 85.1 ft/s) / 0.24 s

a = -354 ft/s²

Rounded to two significant figures, the magnitude of the acceleration is 350 ft/s².

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Sedimentary rocks are types of rock that are formed by the deposition and subsequent cementation of that material at the Earth's surface and within bodies of water. Deposition means that all the sediments, soil, and rocks are all compressed (tightly pressed into each other) and create sedimentary rocks.

I hope this helps! :)
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2 years ago
Pour chacune des réactions chimiques
Doss [256]

Answer: Me non espanol

Explanation:

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A 500 gram mass attached to a horizontal spring
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3 years ago
The magnitude of the magnetic flux through the surface of a circular plate is 6.80 10-5 T · m2 when it is placed in a region of
PIT_PIT [208]

Answer:

B = 4.1*10^-3 T = 4.1mT

Explanation:

In order to calculate the strength of the magnetic field, you use the following formula for the magnetic flux trough a surface:

\Phi_B=S\cdot B=SBcos\alpha        (1)

ФB: magnetic flux trough the circular surface = 6.80*10^-5 T.m^2

S: surface area of the circular plate = π.r^2

r: radius of the circular plate = 8.50cm = 0.085m

B: magnitude of the magnetic field = ?

α: angle between the direction of the magnetic field and the normal to the surface area of the circular plate = 43.0°

You solve the equation (1) for B, and replace the values of the other parameters:

B=\frac{\Phi_B}{Scos\alpha}=\frac{6.80*10^{-5}T.m^2}{(\pi (0.085m)^2)cos(43.0\°)}\\\\B=4.1*10^{-3}T=4.1mT

The strength of the magntetic field is 4.1mT

4 0
2 years ago
________ occurs when a person is holding an object that is directly hit or splashed by lightning.
Papessa [141]

When someone is holding something that has been struck or splashed by lightning, contact damage occurs.

We need additional information concerning lightning and injuries in order to identify the solution.

<h3>What types of injuries are brought on by lightning?</h3>
  • Lightning is the name for a natural electrical discharge that occurs quickly and with a dazzling flash.
  • It has a tremendous amount of energy.
  • Lightning-related injuries can be divided into three categories: direct strikes, side splashes, and contact injuries.
  • When someone is struck by lightning directly, they can get direct injury.
  • When a current splashes from a neighboring object, it is called a side splash.
  • When someone touches a lightning-hit object, contact harm results.

In light of this, we can say that contact injuries happen when a person is holding an object that has been struck by lightning or splashed by it.

Learn more about the lightning and harm here:

brainly.com/question/28055828

#SPJ1

7 0
2 years ago
Read 2 more answers
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