Answer:
15.27895 x 10⁶kg of chlorine radical is added to the atmosphere in a year due to 100 million MVACs
Explanation:
Chlorofluorocarbons (CF₂Cl₂) from refrigerants produce chlorine radicals according to the following equation
CF₂Cl₂ → CF2Cl + Cl
⁻ .........(1)
From equation 1, one mole of CF₂Cl₂ produces one mole of Chlorine radical
From the question,
The emission rate of CF₂Cl₂ is 59.5mg/hour/MVAC
In one day the emission rate would be 59.5 x 24hours
= 1428mg/day
In one year, the emission rate would be 1428mg/day x 365days
= 521220mg/year
= 521.220g/year/MVAC
Therefore the emission rate for 100 million MVAC using CF₂CL₂ in a year is
= 52122 x 10⁶g/year/MVAC
= 52122 x 10³kg/year/MVAC
The molar mass of CF₂CL₂ = 120.913g/mol
No of moles of CF₂CL₂ = mass/ molar mass
= 52122 x 10⁶g / 120.913g/mol
= 431 x 10⁶ moles of CF₂Cl₂
From equation 1, since one mole of CF₂Cl₂ produces one mole of Chlorine radical, it implies that
431 x 10⁶ moles of CF₂Cl₂ would produce 431 x 10⁶ moles of chlorine radical,
Therefore, to find the mass of chlorine radical produced, we use the formula
No of moles of chlorine radical = mass/ molar mass
431 x10⁶ moles = mass of chlorine radical /molar mass of chlorine radical
431 x 10⁶ moles = mass/ 35.45g/mol
mass of chlorine = 431 x 10⁶ moles x 35.45 g/mol
= 15278.95 x 10⁶ g
In Kg, the mass = 15,278.95 x 10³kg of cholrine radical
= 15.27895 x 10⁶ Kg of chlorine radical
