The atom that is oxidized : Cr
The oxidizing agent : H₃PO₄
<h3>Further explanation</h3>
Reaction
2 H₃PO₄ (aq) + 2Cr(s) → 2 CrPO₄ (aq) + 3H₂(g)
Atoms undergoing a reduction reaction (decrease in oxidation number) and an oxidation reaction (increase in oxidation number)
H⁺(in H₃PO₄) =+1
H₂=0
Cr = 0
Cr³⁺(in CrPO₄ )
the oxidizing agent.⇒which undergoes a reduction reaction and oxidizes another compound/element : H₃PO₄
Answer:
T₂ = 242 K
Explanation:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Given data:
Initial volume = 125 mL
Initial pressure = 1.77 atm
Initial temperature = 213 °C (213 +273 = 486 K)
Final volume = 136 mL
Final pressure = 0.810 atm
Final temperature = ?
Solution:
P₁V₁/T₁ = P₂V₂/T₂
T₂ = P₂V₂T₁ / P₁V₁
T₂ = 0.810 atm × 136 mL × 486 K / 1.77 atm× 125 mL
T₂ = 53537.76 atm .mL. K / 221.25 atm . mL
T₂ = 242 K
B., the mass of the nucleus of the atom.
Both the protons and the neutrons are inside the nucleus. The atomic number of an atom is the number of protons, and if you subtract the atomic number from the atomic mass you can find the number of neutrons an atom has.
So, the mass of the protons plus the mass of the neutrons, which are both inside the nucleus, equals the atomic mass.
Well, one mole would be considered as 6.02 x 1023 (atoms). Which in the copper form, this would be considered to be as 63.66 grams of copper. Know, by knowing this information, we're now able to figured out the question.
53.3 ÷ (atoms) 6.02 x 1023 ...
Which as a result, we then have 2665 over.
