1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
xxMikexx [17]
3 years ago
8

A 13,500 kg railroad freight car travels on a level track at a speed of 4.5 m/s. It collided and coupled with a 25,000 kg second

car, initially at rest and with brakes released. What is the speed of the two cars after collision
Physics
1 answer:
expeople1 [14]3 years ago
7 0

Answer: 1.6m/s

Explanation:

M1 = 13500kg

U1 = 4.5m/s

M2 = 25000kg

U2 = 0m/s (since the body is at rest)

V = ? (Common velocity or velocity after impact)

M1U1 + M2U2 = (M1 + M2)V

But U2 = 0

M1U1 = (M1 + M2)V

13500 * 4.5 = (13500 + 25000)v

60750 = 38500v

V = 60750 / 38500 = 1.5779 = 1.6m/s

You might be interested in
What layers on earth are considered liquids
Tatiana [17]
<span>Crust. The thin solid outermost layer of Earth. ...Asthenosphere. The lower layer of the crust. ...Lithosphere.Plasticity: is solid but still being able to. flow without being a liquid.The cool, rigid outermost layer of the Earth. ...<span>the solid part of the earth consisting of the crust and outer mantle.</span></span>
6 0
3 years ago
RANGKAIAN RLC SERI PADA TEGANGAN BOLAK BALIK 220V R=80 OHM XL= 90 OHM XC = 30 OHM MAKA TEGANGAN PADDA INDUKTOR ADALAH???
Whitepunk [10]
Okay, 90% of this is nonsense besides the numbers maybe.
8 0
3 years ago
High mass stars are more massive produce more energy burn brighter and have shorter life cycle than low mass stars
Zarrin [17]
Yes, they do all of those things.
5 0
3 years ago
How far will you travel if you run for 10. minutes at 2.0 m/s?
oee [108]
We know that 1 minute= 60 seconds (or 1 min= 60 s).

10 min* (60 s/ 1 min)* (2.0 m/ 1 s)= 1,200 m.
(Note that the units cancel out so you get the answer)

The final answer is 1,200 m.

Hope this helps~
6 0
3 years ago
An object accelerating at 16 m/s/s doubles its mass and triples its net force acting on it. What will the new acceleration be? (
nataly862011 [7]

Answer:

24 m/s²

Explanation:

The given parameters are;

The initial acceleration of the object, a = 16 m/s²

Let 'm' represent the initial mass of the object

The initial force acting on the object, F = m × a

∴ F = 16 × m = 16·m

When the mass is doubled, we have;

The new mass of the object, m₂ = 2 × m = 2·m

When the net force acting on the object triples, we have;

The new net force acting on the object, F₂ = 3 × F = 3 × 16·m = 48·m

From F = m × a, we have;

a = F/m

∴ The new acceleration of the object, a₂ = F₂/m₂

From which, by plugging in the values, we have;

a₂ = 48·m/(2·m) = 24

The new acceleration of the object, a₂ = 24 m/s².

6 0
3 years ago
Other questions:
  • A closed loop conductor that forms a circle with a radius of is located in a uniform but changing magnetic field. If the maximum
    6·1 answer
  • the density of gold is 19.3 g/cm3. suppose a certain gold wedding ring deplaced 0.55mL of liquid when dropped in a glass of spar
    12·1 answer
  • When water molecules are disappearing into the air, there is a net _______?
    12·1 answer
  • Which is the best example of translational motion?
    9·2 answers
  • Use 3rd law to explain how a fish swims through water. Identify the force pairs and draw a diagram.
    6·1 answer
  • ____________ interference occurs when two waves are out of phase
    12·1 answer
  • A 30.0-kg child sits on one end of a long uniform beam having a mass of 20.0 kg, and a 40.0-kg child sits on the other end. The
    8·1 answer
  • A car completes a journey in 2 hours. Its average speed over this journey was 45 mph. Calculate the distance travelled by the ca
    10·1 answer
  • A hypothesis is a(n) ______________
    15·1 answer
  • A current carrying wire of length 50cm is positioned perpendicular to a uniform magnetic field
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!