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SIZIF [17.4K]
3 years ago
9

Seriously don't understand this worksheet at all please help!

Chemistry
1 answer:
sergij07 [2.7K]3 years ago
8 0
I’m in the 5th grade yo
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When preparing a TLC slide of a reference standard material (RSM), a solvent or mixture of solvents is used to dissolve the RSM
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<span>The better the RSM dissolves in the solvent, the higher the Rf (retention factor) will be, and the further the RSM will move. If the RSM is a polar compound, increasing the polarity of the solvent will increase the Rf of the RSM. If the RSM isn't a polar compound, an increasingly polar solvent will decrease the Rf.</span>
5 0
3 years ago

SSSSS [86.1K]

Answer:

pH is the number given to a substance of how powerful it is before 7 or beyond 7.

the solution is an acid.

Explanation:

Pls mark BRAINLIEST

7 0
3 years ago
Read 2 more answers
Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/m
koban [17]

Here is the full question:

Air containing 0.04% carbon dioxide is pumped into a room whose volume is 6000 ft3. The air is pumped in at a rate of 2000 ft3/min, and the circulated air is then pumped out at the same rate. If there is an initial concentration of 0.2% carbon dioxide, determine the subsequent amount in the room at any time.

What is the concentration at 10 minutes? (Round your answer to three decimal places.

Answer:

0.046 %

Explanation:

The rate-in;

R_{in} = \frac{0.04}{100}*2000

R_{in} = 0.8

The rate-out

R_{out} = \frac{A}{6000}*2000

R_{out} = \frac{A}{3}

We can say that:

\frac{dA}{dt}= 0.8-\frac{A}{3}

where;

A(0)= 0.2% × 6000

A(0)= 0.002 × 6000

A(0)= 12

\frac{dA}{dt} +\frac{A}{3} =0.8

Integration of the above linear equation =

e^{\int\limits \frac {1}{3}dt } = e^{\frac{1}{3}t

so we have:

e^{\frac{1}{3}t}\frac{dA}{dt}} +\frac{1}{3}e^{\frac{1}{3}t}A = 0.8e^{\frac{1}{3}t

\frac{d}{dt}[e^{\frac{1}{3}t}A] = 0.8e^{\frac{1}{3}t

Ae^{\frac{1}{3}t} =2.4e\frac{1}{3}t +C

∴ A(t) = 2.4 +Ce^{-\frac{1}{3}t

Since A(0) = 12

Then;

12 =2.4 + Ce^{-\frac{1}{3}}(0)

C= 12-2.4

C =9.6

Hence;

A(t) = 2.4 +9.6e^{-\frac{t}{3}}

A(0) = 2.4 +9.6e^{-\frac{10}{3}}

A(t) = 2.74

∴ the concentration at 10 minutes is ;

=  \frac{2.74}{6000}*100%

= 0.0456667 %

= 0.046% to three decimal places

7 0
3 years ago
Ill give u brainliest help asap
Anna007 [38]

I think its A. it cant be C or D b/c we are measuring the distance between Earth and Saturn, not the speed.

7 0
3 years ago
A gas that exerts a pressure of
spayn [35]

Answer:

3.089 L

Explanation:

From the given information, provided that the no of moles and the temperature remains constant;

P_1 = 15.6 psi

V_1 = ???

P_2 = 25.43 psi

V_2 = 1.895 L

Using Boyle's law:

P_1V_1 =P_2V_2 \\ \\ V_1 = \dfrac{P_2V_2}{P_1} \\ \\  V_1 = \dfrac{25.43 \times 1.895}{15.6}  \\ \\ \mathbf{  V_1 = 3.089  \ L}

4 0
2 years ago
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