Answer:
C. They are exergonic and provide energy that can be used to produce ATP form ADP and Pi.
Explanation:
There are 2 types of metabolic reactions.
- Anabolic reactions (Anabolism)
- Catabolic reactions (Catabolism)
CATABOLIC REACTIONS:
They consist of reactions in which larger molecules are broken down into simpler ones. They are exergonic i.e. energy producing reactions. The released energy can be stored in the form of ATP (energy currency of cell).
ANABOLIC REACTIONS:
They consist of reactions in which larger molecules are synthesized from simpler ones. They are endergonic reactions i.e. energy is absorbed.
MEMORY AID:
An easy way to remember catabolic reactions is to think of them as "catastrophic reactions" i.e. larger molecules are destructed to produce simpler ones.
Coming back to the question,
<u>a. They require energy from ATP hydrolysis to break down polymers into monomers. </u>
Energy requiring reactions are anabolic and so this is the incorrect answer.
<u>b. They are endergonic and release energy that can be used for cellular work.</u>
Endergonic reactions are anabolic and hence this is the incorrect answer.
<u>c. They are exergonic and provide energy that can be used to produce ATP from ADP and Pi</u>
This statement correctly fits the definition of Catabolic reactions and is therefore the correct answer.
<u>d. They combine small molecules into larger, more energy-rich molecules.</u>
This statement describes anabolic reactions and hence the incorrect choice.
Answer: The differences is Air masses cover over thousands and hundreds and millions of square kilo. A front is a boundary which two air masses but different temperature and moisture content meet.
Explanation:
Answer:
Explanation:
Double Bond => An Alkene molecule
So, the suffix will be "-ene"
7 Carbons => So, we'll use the prefix "Hept-"
Combining the suffix and prefix, we get:
=> Heptene
At equivalence there is no more HA and no more NaOH, for this particular reaction. So that means we have a beaker of NaA and H2O. The H2O contributes 1 x 10-7 M hydrogen ion and hydroxide ion. But NaA is completely soluble because group 1 ion compounds are always soluble. So NaA breaks apart in water and it just so happens to be in water. So now NaA is broken up. The Na+ doesn't change the pH but the A- does change the pH. Remember that the A anion is from a weak acid. That means it will easily attract a hydrogen ion if one is available. What do you know? The A anion is in a beaker of H+ ions! So the A- will attract H+ and become HA. When this happens, it leaves OH-, creating a basic solution, as shown below.
