A 2,000 g quantity of C-14 is left to undergo radioactive decay. The half-life of C-14 is approximately 5,700 years. After going
2 answers:
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Explanation:
When a constant force acts upon an object the acceleration of the object varies inversely with its mass.
or
If m₁ = 21 kg, a₁ = 3 m/s², m₂ = 9 kg
We need to find a₂
So,
So, if mass is 9 kg, its acceleration is 7 m/s².
Considering conservation of mechanical energy we have:
K+U (start)= K+U (end)
Where:
K=kinetic energy=
U=potential energy=
So:
0.05*0.95*9.81+0 (start) = 0+K (end)
K (end)=0.5 Joules
K+U (start)= K+U (end)
Where:
K=kinetic energy=
U=potential energy=
So:
0.05*0.95*9.81+0 (start) = 0+K (end)
K (end)=0.5 Joules