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zalisa [80]
2 years ago
13

um carro com uma velocidade de 80 km\h passa pelo km 240 de uma rodovia as 7:30. a que horas este carro chegara a proxima cidade

, sabendo-se que a mesma esta situada no km 300 dessa rodovia?
Physics
1 answer:
Shkiper50 [21]2 years ago
3 0
From km 240 to km 300 there are 60 km.

The time to travel 60 km at 80km/h is t = d/V = 60km / 80 km/h = 3/4 h.

That is 45 minutes. Then the car will arrive at 7:30 + 45 min = 8:15.
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Needddd helppppppp!!!
yulyashka [42]

Answer:

2/9 times as strong.

Explanation:

From the question given above, the following assumptions were made:

Initial mass of 1st planet (M₁ ) = M

Initial mass of 2nd planet (m₁ ) = m

Initial distance apart (r₁) = r

Initial Force of attraction (F₁) = F

Final mass of 1st planet (M₂) = 2M

Final mass of 1st planet (m₂) = constant = m

Final distance apart (r₂) = 3r

Final force of attraction (F₂) =?

Next, we shall obtain an expression to determine the new force. This can be obtained as follow:

F = GMm / r²

Cross multiply

Fr² = GMm

Divide both side by Mn

G = Fr² / Mm

Since G is constant, then we have

F₁r₁² / M₁m₁ = F₂r₂² / M₂m₂

Finally, we shall determine the new force as follow:

Initial mass of 1st planet (M₁ ) = M

Initial mass of 2nd planet (m₁ ) = m

Initial distance apart (r₁) = r

Initial Force of attraction (F₁) = F

Final mass of 1st planet (M₂) = 2M

Final mass of 1st planet (m₂) = constant = m

Final distance apart (r₂) = 3r

Final force of attraction (F₂) =?

F₁r₁² / M₁m₁ = F₂r₂² / M₂m₂

Fr² / Mm = F₂ × (3r)² / 2M × m

Fr² / Mm = F₂ × 9r² / 2Mm

Cross multiply

Fr² × 2Mm = F₂ × 9r² × Mm

Divide both side by 9r² × Mm

F₂ = Fr² × 2Mm / 9r² × Mm

F₂ = F × 2 / 9

F₂ = 2/9 F

Thus, the new force is 2/9 times the original force i.e 2/9 times as strong.

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8 0
3 years ago
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julia-pushkina [17]

Answer:

<h2>A. Nearsightedness</h2>

Explanation:

A nearsightedness is an eye defect that occurs when someone is only able to see close ranged object but not far distance object. According to the question, if the length of my eye decreases slightly as I age, this means there is a possibility that I will find it difficult to view a far distance object as I age.

At 70, once my eyes had decreased slightly in length, this means I will only be able to see close ranged object but not far distant object, showing that I am now suffering from nearsightedness according to its definition above.

4 0
3 years ago
A mass is undergoing simple harmonic motion. When its displacement is 0, it is at its equilibrium position. At that moment, its
likoan [24]

Answer:

When X = 0

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From x = A sin ω t        sin = 0     so displacement = zero

V = ω A cos ω t             cos = 1 and speed = maximum

a = - A ω^2 sin ω t            sin = 0 and acceleration = zero

4 0
1 year ago
A bicycle has a momentum of 36 kg* m/s and a very!I city of 4 m/s.What is the mass of the bicycle?
Strike441 [17]

p = 36 kgm/s

v = 4m/s

we know that,

p = mv

so,

m =  \frac{p}{v}

m  =  \frac{36}{4}

m = 9kg

8 0
3 years ago
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