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Tamiku [17]
3 years ago
12

What is the relative size and composition of the universe, a galaxy, and a solar system? Is the universe endless?

Physics
2 answers:
vichka [17]3 years ago
7 0
Yas, the universe is endless/infinte
aleksklad [387]3 years ago
3 0

Answer:

The end of the solar system is about 122 astronomical units (AU) away from the sun, where one AU is 93 million miles (150 million kilometers).

Most of the galaxies are 1,000 to 100,000 parsecs in diameter

The size of the universe is unknown

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The 3 states of mater are
lesantik [10]

Answer:

if u are talking about science this is the answer solid, liquid, or gas

4 0
3 years ago
Read 2 more answers
Claudia stubs her toe on the coffee table with a force of 100.ON. A) What is the
slamgirl [31]

Answer:

A.) acceleration= 55.6m/s^2

B.) acceleration of table= 5.0m/s^2

C.) More acceleration

Explanation:

A.) 100N/1.8kg= -55.6

B.) 100N÷20kg= 5

C.) Because since the table would have less mass, it would have had to accelerate more

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Gravity is an example of a conservative force
shtirl [24]

Answer:

True

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3 0
3 years ago
) The potential difference between the plates of a capacitor is 400 V. (a) If the spacing between the plates is doubled without
kramer

(a) 800 V

The capacitance of a parallel-plate capacitor is given by

C=\frac{\epsilon_0 A}{d}

where

\epsilon_0 is the vacuum permittivity

A is the area of each plate

d is the separation between the plates

We see that the capacitance is inversely proportional to the separation, d: in this problem, the separation between the plates is doubled (2d), so the capacitance will become half of its original value:

C'=\frac{C}{2}

The potential difference between the plates is related to the capacitance by

V=\frac{Q}{C} (1)

where Q is the charge stored on the plate. In this problem, the charge is not changed: therefore, the new potential difference is

V'=\frac{Q}{C/2}=2\frac{Q}{C}=2V

So, the potential difference has doubled, and since the initial  value was

V = 400 V

The new value is

V' = 2(400) = 800 V

(b) The charge will decrease by a factor 2

As before, the plate spacing is doubled, so according to the equation

C=\frac{\epsilon_0 A}{d}

Then the capacitance is halved again:

C'=\frac{C}{2}

This time, however, the voltage is held constant. We can rewrite the eq.(1) as

Q = CV

And since V has not changed, we can find what is the new charge stored in the capacitor:

Q' = C'V=\frac{C}{2}V=\frac{1}{2}(CV) = \frac{1}{2}Q

So, the charge will be halved compared to the original charge.

5 0
3 years ago
A truck is moving at a constant speed of 50 m/s. A boy riding in the back of the truck throws a newspaper out the back of the tr
lbvjy [14]

Answer:

70m/s

Explanation:

7 0
4 years ago
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