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3 years ago

What is the relative size and composition of the universe, a galaxy, and a solar system? Is the universe endless?

Physics

2 answers:

vichka [17]3 years ago

7 0

Yas, the universe is endless/infinte

aleksklad [387]3 years ago

3 0

Answer:

The end of the solar system is about 122 astronomical units (AU) away from the sun, where one AU is 93 million miles (150 million kilometers).

Most of the galaxies are 1,000 to 100,000 parsecs in diameter

The size of the universe is unknown

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The formula for speed is v = s/t. <br> a. True<br> b. False

crimeas [40]

If you mean S is the distance then it is true
Velocity = Distance / time

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3 years ago

During a circus act, an elderly performer thrills the crowd by catching a cannon ball shot at him. The cannon ball has a mass of

Ipatiy [6.2K]

Answer:

m v1 = (m + M) v2

v2 = m v1 / (m + M)

v2 = 7 * 74 / (74 + 65)

3.73 m/s

74 kg is too heavy for the cannonball (over 150 lbs)

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3 years ago

After reading a book about parrots, Tani wants to learn more about them. Which question could be answered through scientific inv

melomori [17]

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3 years ago

Read 2 more answers

A 90. 0-kg ice hockey player hits a 0. 150-kg puck, giving the puck a velocity of 45. 0 m/s. If both are initially at rest and i

Mice21 [21]

The distance traveled by the hockey player is 0.025 m.

<h3>The principle of conservation of linear momentum;</h3>

The principle of conservation of linear momentum states that, the total momentum of an isolated system is always conserved.

The final velocity of the hockey play is calculated by applying the principle of conservation of linear momentum;

$m_1v_1 = m_2 v_2\\\\v_1 = \frac{m_2 v_2}{m_1} \\\\v_1 = \frac{0.150 \times 45}{90} \\\\v_1 = 0.075 \ m/s$

The time taken for the puck to reach 15 m is calculated as follows;

$t = \frac{d}{v} \\\\t = \frac{15\ m}{45 \ m/s} \\\\t = 0.33 \ s$

The distance traveled by the hockey player at the calculated time is;

$d = vt\\\\d = 0.075 \ m/s \ \times 0.33 \ s\\\\d = 0.025 \ m$

Learn more about conservation of linear momentum here: brainly.com/question/7538238

4 0

2 years ago

What is the longest wavelength that can be observed in the third order for a transmission grating having 5200 slits/cm?

Anarel [89]

Answer:

641 nm.

Explanation:

Given that,

A transmission grating has 5200 slits/cm.

We need to find the longest wavelength that can be observed in the third order. Using grating equation as follows :

$d\sin\theta=m\lambda$ ...(1)

d is slit spacing

No fo slit per unit length :

$N={5200}\ slit/cm\\\\=520000\ slits/m$

We know that, N = 1/d

For longest wavelength, θ = 90°

From equation (1)

$\dfrac{\sin\theta}{m\lambda}=\dfrac{1}{d}\\\\520000=\dfrac{\sin(90)}{3\lambda}\\\\\lambda=\dfrac{1}{520000\times 3}\\\\=6.41\times 10^{-7}\ m\\\\=641\ nm$

Hence, the longest wavelength in third order for a transmission grating is 641 nm.

3 0

3 years ago