Explanation:
Given:
m = 1.673 × 10^-27 kg
Q = q = 1.602 × 10^-19 C
r = 0.75 nm
= 0.75 × 10^-9 m
A.
Energy, U = (kQq)/r
Ut = 1/2 mv^2 + 1/2 mv^2
1.673 × 10^-27 × v^2 = (8.99 × 10^9 × (1.602 × 10^-19)^2)/0.75 × 10^-9
v = 1.356 × 10^4 m/s
B.
F = (kQq)/r^2
F = m × a
1.673 × 10^-27 × a = ((8.99 × 10^9 × (1.602 × 10-19)^2)/(0.075 × 10^-9)^2
a = 2.45 × 10^17 m/s^2.
60 N because 98N=mg (here g= 9.8 on earth) thus mass can be calculated which is 98/9.8 = 10kg
Now,new weight with g = 6m/s^2
=m×g' (here g' is new acceleration of the new planet)
= 10×6=60N
Answer:
divide
Explanation:
whenever looking for velocity.just devide
Answer:
the weight of the object, the force of gravity acting on said object, and the mass of the object are needed for Newton's second law of motion.
To solve this problem we will calculate the total volume of inhaled and exhaled water. From the ideal gas equation we will find the total number of moles of water.
An athlete at high performance inhales 4.0L of air at 1atm and 298K.
The inhaled and exhaled air contain 0.5% and 6.2% by volume of water, respectively.
During inhalation, volume of water taken is


During exhalation, volume of water expelled is


During 40 breathes, total volume of water taken is

During 40 breathes, total volume of water expelled out is

Therefore resultant volume of water expelled out from the lung is

From the body through the lung we have that

Here,
P = Pressure
R= Gas ideal constant
T= Temperature
V = Volume
Replacing,


Therefore the moles of water per minute are expelled from the body through the lungs is 0.373mol/min