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3 years ago

Pls answer ASAP pls and thnk you my friends

Physics

1 answer:

rodikova [14]3 years ago

6 0

Answer:

Since this is old, hope you don't mind if I scoop up these points

Explanation:

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When a mass of 29 g is attached to a certain spring, it makes 20 complete vibrations in 3.1 s. What is the spring constant of th

never [62]

Answer:

The spring constant of the spring is 47.62 N/m

Explanation:

Given that,

Mass that is attached with the spring, m = 29 g = 0.029 kg

The spring makes 20 complete vibrations in 3.1 s. We need to find the spring constant of the spring. We know that the number of oscillations per unit time is called frequency of an object. So,

$f=\dfrac{20}{3.1}$

f = 6.45 Hz

The frequency of oscillator is given by :

$f=\dfrac{1}{2\pi}\sqrt{\dfrac{k}{m}}$

k is the spring constant

$k=4\pi^2f^2m$

$k=4\pi^2\times (6.45)^2\times 0.029$

k = 47.62 N/m

So, the spring constant of the spring is 47.62 N/m. Hence, this is the required solution.

4 0

3 years ago

¿cuales son los motivos para hacer una carta formal?<br>es para hoy porfavor necesito su ayuda

galina1969 [7]

La carta motivos es un documento escrito dentro del formato epistolar, por el cual se expresan las razones por la cual un postulante solicita algo, por ejemplo: continuar con sus estudios de posgrados en una universidad fuera de su ciudad natal o para dar una razón por la cual se encuentra calificado para un puesto de trabajo.

Nomas ponlo en tus palabras

8 0

3 years ago

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Define personal health.<br>

nekit [7.7K]

Answer:

Personal Health is the ability to take charge of your health by making conscious decisions to be healthy.

7 0

3 years ago

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A 0.280-kg croquet ball makes an elastic head-on collision with a second ball initially at rest. The second ball moves off with

Jet001 [13]

Answer:

mass of second ball is 0.84 kg

Explanation:

mass of ball = 0.280 kg

to find out

mass of the second ball

solution

we know here elastic head on collision and

second ball moves = half the original speed

we consider here m1 mass of 1st ball and m2 mass of second ball

v1 = velocity of first ball before collision

v2 = velocity of second ball before collision

v3 = velocity of first ball after collision

v4 = velocity of second ball after collision

so here

we know 2nd ball was on rest so v2 = 0

after collision v4 = 1/2 ( v1)

and we know head on collision so

v3 = - v1/2

so from law of conservation of mass

m1v1 + m2v2 = m1v3 + m2v4

put here value

m1v1 + m2(0) = m1(-v1/2) + m2(v1/2)

solve and we get

m2 = 3m1

m2 = 3( 0.280) = 0.84

mass of second ball is 0.84 kg

7 0

4 years ago

A net force of 100 N is applied to a wagon for five seconds. This causes the wagon to undergo a change in momentum of

baherus [9]

Answer:

500 Ns

Explanation:

According to the impulse theorem, the change in momentum of an object is equal to the impulse exerted on it. Mathematically:

$\Delta p = I = F \Delta t$

where

$\Delta p$ is the change in momentum of the object

I is the impulse exerted, which is the product of

F, the net force exerted

$\Delta t$ , the time interval during which the force is applied

In this problem,

F = 100 N is the force applied on the wagon

$\Delta t=5 s$ is the time interval

Substituting, we find the change in momentum of the wagon:

$\Delta p = (100)(5)=500 Ns$

5 0

4 years ago