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Margarita [4]
3 years ago
10

A circuit was set up as shown in the diagram . The tgree resistors are identical

Physics
1 answer:
wolverine [178]3 years ago
7 0
6 / 3 = 2
So the reading on the voltmeter will be 2.
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A 13,000 kg helicopter accelerates upward a 0.5 m/s^2 while lifting a 2000 pound car. to the nearest newton, what is the lift fo
Vinil7 [7]

Lift force exerted by the air on the rotors=143244 N

Explanation:

we use Newtons second law

F- (M+m)g=(M+m)a

F= lift force

m= mass of helicopter= 13000 Kg

M= mass of car= 2000 lb=907.2 kg

a= acceleration= 0.5 m/s²

g= acceleration due to gravity

F- (M+m)g=(M+m)a

F=(M+m)(a+g)

F=(13000+907.2)(0.5+9.8)

F=143244 N

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3 years ago
A rocket is being launched straight up. Air resistance is not negligible.
Yanka [14]

Answer:

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When a closed loop of wire experiences a changing magnetic field a voltage and therefore current is produced. This is the basis
MakcuM [25]

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We can predict the path of a hurricane because of the work of which of the following scientists?
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3 years ago
A man strikes one end of a thin rod with a hammer. The speed of sound in the rod is 15 times the speed of sound in air. A woman,
lina2011 [118]

Answer:

44.1 m

Explanation:

<u>Given:</u>

  • V_a = speed of sound in air = 343 m/s
  • V_r = speed of sound in the rod = 15V_a
  • \Delta t = times interval between the hearing the sound twice = 0.12 s

<u>Assumptions:</u>

  • l = length of the rod
  • t = time taken by the sound to travel through the rod
  • T = time taken by the sound to travel to through air to the same point = t+\Delta t = t+0.12\ s

We know that the distance traveled by the sound in a particular medium is equal to the product of the speed of sound in that medium and the time taken.

For traveling sound through the rod, we have

l=V_r t\\\Rightarrow t = \dfrac{l}{V_r}..........eqn(1)

For traveling sound through the air to the women ear for traveling the same distance, we have

l=V_aT\\\Rightarrow l=V_a(t+0.12)\\\Rightarrow l=V_a(\dfrac{l}{V_r}+0.12)\,\,\,\,\,\,(\textrm{From eqn (1)})\\\Rightarrow l=V_a(\dfrac{l}{15V_a}+0.12)\\\Rightarrow l=\dfrac{l}{15}+0.12V_a\\\Rightarrow l-\dfrac{l}{15}=0.12V_a\\\Rightarrow \dfrac{14l}{15}=0.12V_a\\\Rightarrow l = \dfrac{15}{14}\times 0.12V_a\\\Rightarrow l = \dfrac{15}{14}\times 0.12\times 343\\\Rightarrow l = \dfrac{15}{14}\times 0.12\times 343\\\Rightarrow l = 44.1\ m

Hence, the length of the rod is 44.1 m.

4 0
3 years ago
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