All categories

3 years ago

A circuit was set up as shown in the diagram . The tgree resistors are identical

Physics

1 answer:

wolverine [178]3 years ago

7 0

6 / 3 = 2
So the reading on the voltmeter will be 2.

You might be interested in

What is formed when sediment stick together

Taya2010 [7]

Think its either sedimentary rocks or metamorphic rocks.

5 0

3 years ago

Lori wants to send a box of oranges to a friend by mail. The box of oranges cannot exceed a mass of 10.222 Kg. If each orange ha

Sergeu [11.5K]

Explanation:

Given that,

The box of oranges cannot exceed a mass of 10.222 Kg if we are sending to a friend by mail.

The mass of each orange is 198 g

We know that,

1 kg = 1000 g

10.222 kg = 10.222×1000 g

Let there are n number of oranges. So,

$n=\dfrac{10.222\times 1000\ g}{198\ g}\\\\n=51.92\approx 52\ \text{oranges}$

It means she can send 52 oranges and it is maximum quantity.

4 0

3 years ago

Estimate the inductance L of a coil that is 12 cm long, made of about 235 copper-wire turns and a diameter of about 1.7 cm. Show

ANTONII [103]

Answer:

Inductance as calculated is 13.12 mH

Solution:

As per the question:

Length of the coil, l = 12 cm = 0.12 m

Diameter, d = 1.7 cm = 0.017 m

No. of turns, N = 235

Now,

Area of cross-section of the wire, A = $\frac{\pi d^{2}}{4} = \frac{\pi \times 0.017^{2}}{4} = 2.269\times 10^{- 4}\ m^{2}$

We know that the inductance of the coil is given by the formula:

$L = \frac{mu_{o}AN^{2}}{l} = \frac{4\pi \times 10^{- 7}\times 2.269\times 10^{- 4}\times 235^{2}}{0.12} = 1.312\times 10^{- 4}\ H = 13.12\ mH$

4 0

3 years ago

Es frecuente que en las instalaciones eléctricas domésticas se utilice alambre de cobre de 2.05 mm de diámetro. Determine la res

Tasya [4]

Answer:

The resistance is 0.124 ohm.

Explanation:

It is common for domestic electrical installations to use copper wire with a diameter of 2.05 mm. Determine the resistance of such a wire with a length of 24.0 m.

diameter, d = 2.05 mm

radius, r = 1.025 mm

Length, L = 24 m

resistivity of copper = 1.7 x 10^-8 ohm m

Let the resistance is R.

$R =\rho \frac{L}{A}\\\\R = \frac {1.7\times10^{-8}\times 24}{3.14\times1.025\times1.025\times 10^{-6}}\\\\R = 0.124 ohm$

7 0

3 years ago

If the rate $56 per 7 hours is reduced to a unit rate, the result is dollars per hour.

34kurt

The answer is 8 because multiplying 7 and 8 is 56

4 0

3 years ago

Read 2 more answers