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GrogVix [38]
2 years ago
12

What is the missing factor in the equation? Assume x0 and y0.

Mathematics
1 answer:
denpristay [2]2 years ago
5 0

Answer:

y^3/4x

Step-by-step explanation:

Given that the expression 6x^2/5y multiplied by some unknown gives answer as 3xy^2/10

We know that if ab = c, the b = c/a

Using the same principle, we have

unknown value = 3xy^2/10 divided by 6x^2/y

Use the fact that a/b divided by c/d = ad/bc

We get unknown = 5y(3xy^2)/6x^2 (10)

=15xy^3/60x^2

Simplify the constant part 15/60 as 1/4

xy^3 /x^2y

X term becomes x/x^2 = 1/x

so multiplying term =y^3/4x

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Which expressions are equivalent to ln x 2 ln 5 ln 1? Check all that apply. 2 ln 5x ln (x 26) ln 25x ln 1 ln 25x.
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Equivalent expression is the expression of two equation when the way of representation of the two equation is different but the result is same.The expressions which are equivalent to the given expression are,

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Given information-

The expression given in the problem is,

\ln x+2 \ln 5 +\ln1

<h3>Equivalent expression-</h3>

Equivalent expression is the expression of two equation when the way of representation of the two equation is different but the result is same.

For given expression,

\ln x+2 \ln 5 +\ln1

As the above function is the function of <em>x. </em>Thus it can be written as,

f(x)=\ln x+2 \ln 5 +\ln1

<h3>Logarithm power rule</h3>

Logarithm power rule states that the exponent of the logarithm function can transfers to front of the logarithm and vice versa. Thus,

f(x)=\ln x+ \ln 5^2 +\ln1\\&#10;f(x)=\ln x+ \ln 25 +\ln1

Now the value of \ln 1 is equal to the zero. Thus,

f(x)=0+\ln 25 +\ln1\\&#10;f(x)=0+\ln 25 +\ln1\\&#10;f(x)=\ln 25 +\ln1\\&#10;f(x)=\ln 25 +0\\&#10;f(x)=\ln 25

Hence the expressions which are equivalent to the given expression are,

  • \ln25+\ln1
  • \ln25

Learn more about the equivalent expression here;

brainly.com/question/10628562

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Answer:

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Step-by-step explanation:

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