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GrogVix [38]
3 years ago
12

What is the missing factor in the equation? Assume x0 and y0.

Mathematics
1 answer:
denpristay [2]3 years ago
5 0

Answer:

y^3/4x

Step-by-step explanation:

Given that the expression 6x^2/5y multiplied by some unknown gives answer as 3xy^2/10

We know that if ab = c, the b = c/a

Using the same principle, we have

unknown value = 3xy^2/10 divided by 6x^2/y

Use the fact that a/b divided by c/d = ad/bc

We get unknown = 5y(3xy^2)/6x^2 (10)

=15xy^3/60x^2

Simplify the constant part 15/60 as 1/4

xy^3 /x^2y

X term becomes x/x^2 = 1/x

so multiplying term =y^3/4x

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Step-by-step explanation:

the slope is always the factor of x.

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so,

10) neither. we have the slopes -2/1 and 1/1.

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Find the slope of the line.
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Between which two consecutive whole numbers does the root of 59 lie​
IrinaK [193]

Answer:

Step-by-step explanation:

¿Entre que números naturales consecutivos se encuentra cada raíz?

Bueno en este caso debes empezar por el 1 en adelante, pero solo sucede en números impares consecutivos. Solamente debes sumar 1,3,5,7,9,11,13,15,17,19 ..... en adelante, y en cada suma de cada sucesión encontraras un cuadrado. Ojo solo sumando en orden, tampoco sumarás 3+9, ya que te dará 12 y 12 No tiene raíz.

1+3=4,√4=2

4+5=9, √9=3

9+7=16, √16=4

16+9=25, √25=5

25+11=36, √36=6

36+13=49, √49=7

49+15=64, √64=8

64+17=81, √81=9

81+19=100, √100=10

............................................................................................................

A SI CONSECUTIVAMENTE SIEMPRE OBTENDRÁS CADA RAÍZ  

¿Entre que números naturales consecutivos se encuentra cada raíz?

R= En los número impares consecutivos, comenzando por el 1 en adelante.

8 0
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