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Igoryamba
3 years ago
9

Which law relates temperature, pressure, volume, and the number of moles of a gas under perfect conditions? Boyle's law Charles'

s, law ideal, gas law, combined gas law
Chemistry
2 answers:
Shalnov [3]3 years ago
7 0

Answer: Avogadro's Law

Explanation: It states that the volume of the gas is directly proportional to the number of moles of the gas at constant pressure and temperature of the gas.

andreyandreev [35.5K]3 years ago
7 0

Answer:

its gas law on ed

Explanation:

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Whoever gets it right gets brainliest!!
Tasya [4]

When different atoms join together, they are called a compound. Compounds are made of molecules (so molecules could be an alternate answer, but not all molecules are compounds)

3 0
3 years ago
Read 2 more answers
If 15 grams of Carbon dioxide is produced in a chemical reaction, how many grams of Carbon must be consumed in the reaction if w
guajiro [1.7K]

Answer:

Quantity of Carbon is 4.09 gm

Explanation:

Equation of carbon reacting with oxygen to give carbon dioxide is given by

C + O_{2} ⇒ CO_{2}

One mole of carbon reacts with one mole of Oxygen in this reaction to give One mole of Carbon dioxide.

So, 12 gm of carbon reacts with 32 gm of Oxygen in this reaction to give 44 gm of carbon dioxide.

15 gm of CO_{2} was formed in this reaction

Oxygen used in this reaction = \frac{15}{44}×32 = 10.91 gm ,

Thus Oxygen is in sufficient quantity in the reaction.

Now,

Carbon that must be used = \frac{15}{44}×12  = 4.09 gm.

5 0
3 years ago
What happens to the average kinetic energy when a solid is warming up?
dsp73
Answer: Average K.E of the solid after heating/warming increases
4 0
3 years ago
a solution of unknown molecular substance is prepared by dissolving 0.50g of the unknown in 8.0g of benzene. the solution freeze
spayn [35]

Answer:

THE MOLAR MASS OF THE UNKNOWN MOLECULAR SUBSTANCE IS 200 G/MOL.

Explanation:

Mass of the unknown substance = 0.50 g

Freezing point of the solution = 3.9 °C

Freezing point of pure benzene = 5.5 °C

Freezing point dissociation constant Kf = 5.12°C/m

First, calculate the temperature difference between the freezing point of pure benzene and the final solution freezing point.

Change in temperature = 5.5 -3.9 = 1.6 °C

Next is to calculate the number of moles or molarity of the compound that dissolved.

Using the formula:

Δt = i Kf m

Assume i = 1

So,

1.6 °C = 1 * 5.12 * x/ 0.005 kg of benzene

x = 1.6 * 0.008 / 5.12

x = 0.0128 / 5.12

x = 0.0025 moles.

Next is to calculate the molar mass using the formula, molarity = mass / molar mass

Molar mass = mass / molarity

Molar mass = 0.50 g /0.0025

Molar mass = 200 g/mol

Hence, the molar mass of the unknown compound is 200 g/mol

6 0
3 years ago
When 35.47 g of sodium hydroxide react with boric acid (H3BO3), how many moles of sodium borate will be produced?
belka [17]

Answer:

5.83 g

Explanation:

First, you must start with a balanced equation so you can see the mole ratios.

NaOH + H₃BO₃ --> NaBO₂ + 2H₂O

You can see that it takes 1 mole of sodium hydroxide to form 1 mole of sodium borate. 1:1 ratio

Now you must calculate how many moles of NaOH 35.47 g equals.

Na = 22.99 amu

O = 15.99 amu

H = 1.008 amu

NaOH = 39.997 amu

35.47 g ÷ 39.997 amu = 0.08868 moles of NaOH

Since it's a 1:1 ratio, the same number of moles of NaBO₂ is created. Now you must convert moles to grams.

Na = 22.9 amu

B = 10.81 amu

2 O = 31.998 amu

NaBO₂ = 65.798 amu

0.08868 moles x 65.798 = 5.83 g

4 0
3 years ago
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