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Usimov [2.4K]
3 years ago
15

For the first 10 seconds a squirrel runs 3 m/s to look for an acorn. The next 5 seconds he eats an acorn that he finds. Afterwar

ds the squirrel runs 2 m/s back to where he started. (A) How long does it take for the squirrel to get back to where he started?
Physics
1 answer:
Gala2k [10]3 years ago
7 0

Distance covered by the squirrel to look for an acorn :

d = ( 3 m/s ) × 10 s = 30 m.

Time taken to eat an Acron is 5 seconds.

Time taken to cover distance of 30 m with 2 m/s speed is :

T=\dfrac{30}{2}\ s= 15 \ s

Therefore, total time take to  get back to where he started is ( 10+5+15 ) = 30 s.

Hence, this is the required solution.

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If a shuttle is orbiting a planet at a distance of 40 miles from the center of the planet, and is traveling at a rate of 500 mil
lawyer [7]

Answer:

Time taken, t = 30.15 minutes

Explanation:

It is given that,

Distance from the center of planet, r = 40 miles

Speed of the shuttle, v = 500 miles per hour

Let t is the time taken by it to complete  one full orbit. The displacement of the shuttle is,

d=2\pi r

d=2\pi \times 40

d = 251.32 miles

Now time can be calculated using the expression for the velocity as :

v=\dfrac{d}{t}

t=\dfrac{d}{v}

t=\dfrac{251.32\ miles}{500\ miles\ per\ hour}

t = 0.50264 hours

or

t = 30.15 minutes

So, the shuttle will take 30.15 minutes to complete one full orbit. Hence, this is the required solution.

7 0
3 years ago
Describe two ways alloys improve upon the properties of pure metal elements ?
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A) Metal expand upon heating. B) Alloys expand less upon heating than elemental metals. C) Alloys expand more upon heating than elementals metals. D) The rate of the expansion of metals is directly proportion to the temperature to which it is heated
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3 years ago
Using information about natural laws, explain why some car crashes produce minor injuries and others produce catastrophic injuri
Nataly_w [17]
Don't they have to pay insurance company if something happens to there car.
5 0
3 years ago
Playing tetherball, a boy hits the 0.45 kg ball, moving toward him initially at 4.6 m/s, in the opposite direction at 2.5 m/s. H
saul85 [17]

Answer:

HI

Explanation:

8 0
3 years ago
A long coaxial cable consists of an inner cylindrical conductor with radius a and an outer coaxial cylinder with inner radius b
Tcecarenko [31]

Answer:

(a) E=λ/(2\pi e0 r)

(b) E = 0

Explanation:

(a) We can use the Gaussian's Law to calculate the electric field at any distance r from the axis. By using a cylindrical Gaussian surface we have:

\int \vec{E}\cdot d\vec{r}=\frac{\lambda}{\epsilon_o}

where  λ is the total charge per unit length inside the Gaussian surface. In this case we have that the Electric field vector is perpendicular to the r vector. Hence:

E\int dr=E2\pi r=\frac{\lambda}{\epsilon_o}\\\\E=\frac{\lambda}{2\pi r \epsilon_o}

(b) outside of the outer cylinder there is no net charge inside the Gaussian surface, because charge of the inner radius cancel out with the inner surface of the cylindrical conductor.

Hence, we  have that E is zero.

hope this helps!!

3 0
3 years ago
Read 2 more answers
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