Question

An ideal (non-viscous, incompressible) fluid flows through a horizontal pipe. The fluid density is 900 kg/m3. Initially, the pipe has a diameter of 0.7 cm and the fluid flows at a speed of 9 m/s at a pressure of 13,000 N/m2. Then, the pipe widens to a diameter of 2.1 cm. What is the speed of the fluid in the wider section of the pipe, in units of m/s

Answer 1

Answer:

the speed of the fluid in the wider section of the pipe is 1m/s.

Explanation:

By equation of continuity we can write (for ideal (non-viscous, in-compressible).

$A_1v_1 =A_2v_2$

A_1,A_2 are areas of the pipe at inlet and outlet of the pipe.

$\Rightarrow \pi d_1^2v_1=\pi d_2^2v_2$_1

Here, d_1 , d_2 are diameters of inlet and outlet, also v_1, v_2 are velocities at inlet and outlet.

putting values we get

$\Rightarrow \p 0.7^2\times9=\pi 2.1^2\timesv_2$

solving we get

$v_2= 1m/s$