Question

As a woman walks, her entire weight is momentarily placed on one heel of her high-heeled shoes. Calculate the pressure exerted on the floor by the heel if it has an area of 1.64 cm2 and the woman's mass is 67.0 kg. Express the pressure in pascals. (In the early days of commercial flight, women were not allowed to wear high-heeled shoes because aircraft floors were too thin to withstand such large pressures.)

Answer 1

Answer:4.003 MPa

Explanation:

Given

Area of heel $A=1.64 cm^2\approx 1.64\times 10^{-4} m^2$

Mass of woman $m= 67 kg$

Pressure is defined as Force applied in over an area such that it is perpendicular to it i.e.

$Pressure=\frac{Force}{Area}$

$P=\frac{F}{A}$

$P=\frac{mg}{A}$

$P=\frac{67\times 9.8}{1.64\times 10^{-4}}$

$P=400.365\times 10^{4} Pa$

$P=4.003 MPa$