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Alex787 [66]
3 years ago
8

Glven 4.62 mol of sodium hydroxide, NaOH, how many grams are present?

Chemistry
1 answer:
Vaselesa [24]3 years ago
3 0
1 mole is equal to 1 moles NaOH, or 39.99711 grams.
Hope this helped
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If the molar absorptivity constant for the red dye solution is 5.56×104 M-1cm-1, calculate the molarity of the red dye solution
Shtirlitz [24]

Explanation:

a) Using Beer-Lambert's law :

Formula used :

A=\epsilon \times c\times l

where,

A = absorbance of solution = 0.945

c = concentration of solution = ?

l = length of the cell = 1.20 cm

\epsilon = molar absorptivity of this solution =5.56\times 10^4 M^{-1} cm^{-1}

0.945=5.56\times 10^4 M^{-1} cm^{-1}\times 1.20 \times c

c=1.4163\times 10^{-5} M=14.16 \mu M

(1\mu M=10^{-6} M)

14.16 μM is the molarity of the red dye solution at the optimal wavelength 519nm and absorbance value 0.945.

b) c=1.4163\times 10^{-5} mol/L

1 L of solution contains 1.4163\times 10^{-5} moles of red dye.

Mass of 1.4163\times 10^{-5} moles of red dye:

1.4163\times 10^{-5}\times 879.86g/mol=0.01246 g

(w/v)\%=\frac{\text{Mass of solute (g)}}{\text{Volume of solvent (mL)}}\times 100

red(w/v)\%=\frac{0.01246 g}{1000 mL}\times 100=0.001246\%

c) In order to dilute red dye solution by 5 times, we will need to add 1 L of water to solution of given concentration.

Concentration of red dye solution = c=1.4163\times 10^{-5} M

Concentration of red solution after dilution = c'

c=c'\times 5

1.4163\times 10^{-5} M=c'\times 5

c'=2.83\times 10^{-6} M

The final concentration of the diluted solution is 2.83\times 10^{-6} M

8 0
3 years ago
Under standard-state conditions, which of the following half-reactions occurs at the cathode during the electrolysis of aqueous
Slav-nsk [51]

Answer:

The following reaction will occur at cathode:

Ni^{+2}(aq)+2e--->Ni(s)

Explanation:

The two half reaction during electrolysis of aqueous nickel sulfate will be

a) anode reaction :

Water will undergo oxidation and will evolve oxygen gas at anode as shown in the given reaction:

2H_{2}O(l) ----> O_{2}(g) + 4H^{+}(aq) + 4e

b) Cathode reaction: The reduction of Nickel ion will occur by gain of two electrons as shown in the given equation:

Ni^{+2}(aq)+2e--->Ni(s)

Thus the overall reaction will be:

2H_{2}O(l) + 2Ni^{+2}----> O_{2}(g) + 4H^{+}(aq) + 2Ni(s)

6 0
3 years ago
How many different compounds are possible, changing only the cis/trans arrangements around these two double bonds?
insens350 [35]
Check the attached file for the answer.

3 0
3 years ago
Which of the following compounds are ionic compounds? Check all of the boxes that apply.
Lady_Fox [76]

Answer:

NaCl is the one of the example of ionic compound because na conducts positive charge and CL conduct negative charge

3 0
2 years ago
Iron is used to make steel for building bridges. Some bridges have blocks of magnesium attached to them. Explain why?
Ede4ka [16]
Blocks of magnesium is used to prevent iron corrosion.
This way of prevention is called sacrificial protection.
6 0
3 years ago
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