Question

You need to produce a solenoid that has an inductance of 2.47 μh . you construct the solenoid by uniformly winding 1.15 m of thin wire around a tube. how long, in centimeters, should the tube be?

Answer 1

Answer:

0.0170m or 1.70cm

Explanation:

L=(μ₀*N^2*A)/(l)

N=x/2*pi*r so r=x/2*pi*N

A=pi*r^2=(pi*x^2)/(4*pi^2*N^2)

L=(μ₀*N^2*A)/(l)=(μ₀*N^2*pi*x^2)/(4*pi^2*N^2*l)=(μ₀*x^2)/(4*pi*l)

l=(μ₀*x^2)/4*pi*L)=[(4*10^-7)*(1.15m)/4*pi*2.47*10^-6H)=0.0170m or 1.70cm

Hope this helps. Any questions please feel free to ask. Thanks!