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3 years ago

Before the student releases the cart by cutting the tinsel string, what forces are acting on the cart?

Physics

1 answer:

Naya [18.7K]3 years ago

5 0

Answer: TENSION and WEIGHT

Explanation:

Force experienced by the spring is called TENSION while the WEIGHT is the gravitational pull on the body towards the earth surface. Therefore the forces acting on the cart are TENSION and WEIGHT(weight acts downwards (along negative y-axis) while the TENSION upward(along positive y-axis).

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How long does it take to drive from one end of california to the other?

evablogger [386]

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3 years ago

If a car is moving to the left with constantvelocity, one can conclude thatthere mustbe no forces applied to the car.the netforc

Allisa [31]

Answer:

the net force applied to the car is zero.

Explanation:

According to Newton's second law, the acceleration of an object (a) is directly proportional to the net force applied (F):

$a=\frac{F}{m}$

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the net force applied to the car is zero.

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3 years ago

Some of our appliances have a magnet in it.<br><br>yes or no

Montano1993 [528]

Answer:

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Explanation:

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2 years ago

Read 2 more answers

Four distinguishable particles move freely in a room divided into octants (there are no actual partitions). Let the basic states

mafiozo [28]

Answer:

Explanation:

Since the door that leads to the room is opened, this gives room for particles to move into the next identical room and divided into octants. Now the amount of space that can be occupied becomes double, the number of basic states has increased by 404916

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3 years ago

A speeding Thunderbird left skid marks on the road that were 76.7 m long when it came to a stop. If the acceleration of the car

FrozenT [24]

Answer: 39.2 m/s

Explanation:

You can use the kinematic equation:

$v_f^2=v_i^2+2a*d$

We know the final velocity because it says it came to a stop. So now all we gotta do is plug in.

$0^2=v_i^2+2(-10)(76.7)\\v_i^2=1,534\\v_i=\sqrt{1534} \\=39.166 m/s$

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3 years ago