Question

Two students play tug of war. Jack pulls East with a force of 82 Newtons while Tony pulls west with a force of 96 Newtons. Which of the following best describe the net force on the center of the rope?
A.178 N West
B.178 N East
C.14 N West
D.14 N East

Answer 1

The net force on the center of the rope is C. 14 N West

Explanation:

We have two forces acting on the rope:

- The force applied by Jack, 82 N, towards East

- The force applied by Tony, 96 N, towards West

Taking East as positive direction, we can rewrite the two forces as

$F_1 = +82 N\\F_2 = -96 N$

where the second force is negative since its direction is west.

The two forces act along the same line, so we can calculate their resultant by simply calculating their algebraic sum. Therefore:

$F=F_1+F_2=+82+(-96)=-14 N$

And the negative sign tells us that the direction is West.

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Answer 2

Answer: The net force acting on the center of the rope is 14 N in west direction.

Explanation:

Balanced force is defined as the forces that gets cancelled out when equal forces are acting in the opposite direction. The net force on the system comes out to be 0.

Unbalanced force is defined as the forces that does not get cancelled out because unequal forces act on the system in opposite direction. The motion of the object is in the direction of net force.

According to the question:

Force applied by Jack in the East direction while playing tug of war = 82 N

Force applied by Tony in the West direction while playing tug of war = 96 N

Net force acting on the center of the rope = 96 - 82 = 14 N (acting in the west direction)

Hence, the net force acting on the center of the rope is 14 N in west direction.