1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
denpristay [2]
3 years ago
14

if you walk straight on a road for 100 m then turn around and walk back to your starting point what is your distance

Physics
1 answer:
taurus [48]3 years ago
3 0

Answer:

what do you need help with.

Explanation:

You might be interested in
Two parallel plates 19 cm on a side are given equal and opposite charges of magnitude 2.0 ✕ 10^−9 C. The plates are 1.8 mm apart
Romashka [77]

Answer:

E   = 5291.00 N/C

Explanation:

Expression for capacitance is

C = \frac{\epsilon  A}{d}

where

A is area of square plate

D = DISTANCE BETWEEN THE PLATE

C = \frac{\epsilon\times(19\times 10^{-2})^2}{1.5\times 10^{-3}}

C = 24.06 \epsilon

C = 24.06\times 8.854\times 10^{-12} F

C =2.1\times 10^{-10} F

We know that capacitrnce and charge is related as

V = \frac{Q}{C}

 = \frac{2\tiimes 10^{-9}}{2.\times 10^{-10}}

v = 9.523 V

Electric field is given as

E = \frac{V}{d}

   = \frac{9.52}{1.8*10^{-3}}

E   = 5291.00 V/m

E   = 5291.00 N/C

5 0
3 years ago
An object begins with a speed of 20 meters per second and slows down to a speed of 10 meters per second over a time of 5 seconds
Andreyy89

Answer:

V = 6 m/s

Explanation:

Given that,

Initial speed of an object is 20 m/s

Final speed of an object is 10 m/s

Time, t = 5 s

We need to find the average speed of the object during these 5 seconds. Let it is equal to V. Here, time is same. The average speed is given by :

V=\dfrac{x+y}{2}\\\\\text{Putting values}\\\\V=\dfrac{20+10}{5}\\\\V=6\ m/s

So, the average speed of the object is 6 m/s.

3 0
3 years ago
Your friends sit in a sled in the snow. If you apply a force pf 75 N to them, they have an acceleration of 0.9 m/s ^ 2. What is
Elza [17]

Answer:

Mass of the sled in the snow 83.33 kg.

<u>Explanation</u>:

Given that,  

Force applied to move the sled in the snow (F) = 75N

\text { Acceleration }(a)=0.9 \mathrm{m} / \mathrm{s}^{2}

We know that

Newton's second law of motion is  

\text { Force }=\text { mass } \times \text { acceleration }

F = ma (Or "force" is equal to "mass" times "acceleration".)

So if we move this around we can isolate mass and get mass

\text { Mass }=\frac{\text { force }}{\text { accelearation }}

\mathrm{M}=\frac{75}{0.9}

M = 83.33 kg

Mass of the sled in the snow <u>83.33 kg.</u>

3 0
3 years ago
Help me to solve this please
aivan3 [116]

Answer:

2) 7

3) 5

Explanation:

6 0
3 years ago
Read 2 more answers
Make a sketch of the radius of gyration of a polymer chain vs. the degree of polymerization N as it would appear on a log-log sc
zvonat [6]

Answer:

hhhhhhhhhhhhhhhhhhhhh

Explanation:

sjdnxjwodj1oeixjwkw9dijwqoisjd1

sjssusidej

4 0
3 years ago
Other questions:
  • Answer these questions fast please:-
    13·1 answer
  • Are mushrooms, producers, consumers, or decomposers?
    7·1 answer
  • Why is sunlight is considered a renewable resource? It is used for energy. It is found in nature. It is abundant. It is helpful
    9·2 answers
  • Two resistors, R1=2.79 Ω and R2=6.37 Ω , are connected in series to a battery with an EMF of 24.0 V and negligible internal resi
    7·1 answer
  • A supply plane needs to drop a package of food to scientists working on a glacier in Greenland. The plane flies 90.0 m above the
    12·1 answer
  • Turning up the Heat
    12·1 answer
  • 6. A lumberjack is standing on a log floating on a lake. She starts from rest, then runs along the log to the end, when she jump
    10·1 answer
  • Can someone please answer this, ill give you brainliest and your getting 100 points.
    9·2 answers
  • Parents take their children camping is a gpi or a gdp
    5·1 answer
  • The same girl in number 3 (above) pushes another friend on the same skateboard.
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!