if you walk straight on a road for 100 m then turn around and walk back to your starting point what is your distance

Which do you think the correct answer was wrong<br> Help plis:(

Alex777 [14]

Answer:

36255 Kg.

Explanation:

From the question given above, the following data were obtained:

Momentum = 1450200 Kgm/s

Velocity = 40 m/s

Mass =?

Momentum is simply defined as the product of mass and velocity. Mathematically, it is expressed as:

Momentum = mass × velocity

With the above formula, we can obtain the mass of the train as follow:

Momentum = 1450200 Kgm/s

Velocity = 40 m/s

Mass =?

Momentum = mass × velocity

1450200 = mass × 40

Divide both side by 40

Mass = 1450200 / 40

Mass = 36255 Kg

Thus the mass of the train is 36255 Kg

7 0

2 years ago

I NEED HELP IS URGENT PLEASE!!!

Readme [11.4K]

D. For any projectile motion, there is a constant downwards acceleration due to gravity at all instances. This not to be confused with velocity, which changes due to gravity at every moment along the object's path.

5 0

3 years ago

The angular velocity of the disk is defined by ω = ( 5 t 2 + 2 ) r a d / s , where t is in seconds. Determine the magnitudes of

ohaa [14]

Answer

given,

Assume radius of the disk be = 0.8 m

angular velocity of disk

ω = ( 5 t² + 2 ) r a d / s

magnitude of velocity and acceleration = ?

At the instant of time, t = 0.5 s

ω = ( 5 x (0.5)² + 2 ) r a d / s

ω = 3.25 r a d / s

$\alpha = \dfrac{d\omega}{dt}$

$\alpha = \dfrac{d}{dt}( 5 t² + 2)$

$\alpha =10 t$

$\alpha =10\times 0.5$

α = 5 rad/s²

velocity

v = ω r

v = 3.25 x 0.8

v = 2.6 m/s

tangential acceleration

$a_t = \alpha r$

$a_t =5 \times 0.8$

$a_t =4\ m/s^2$

normal acceleration

$a_n = \omega^2\ r$

$a_n = 3.25^2\times 0.8$

$a_n =8.45 \m/s^2$

$a = \sqrt{a_n^2 + a_t^2}$

magnitude of the acceleration

$a = \sqrt{8.45^2 + 4^2}$

a = 9.35 m/s²

6 0

3 years ago

Earl is using his hands to hold a metal pan 10 centimeters above a hot burner. How can this scenario be changed to demonstrate c

Olenka [21]

Answer: touch the pan to the burner

Explanation:

There are three modes of heat transfer:

conduction, convection and radiation.

For conduction, the heat transfers from a hot object to a cold object when the two are in contact.

For convection there is bulk motion of fluid occurs which transfers the heat.

For heat transfer by radiation, medium is not required.

Thus, to demonstrate conduction between pan and burner, the pan must touch the burner.

8 0

3 years ago

Read 2 more answers

Two power lines run parallel for a distance of 220 m and are separated by a distance of 40.0 cm. If the current in each of the t

daser333 [38]

Answer:

The magnitude of force is 1.86 N and the direction of force is towards the other wire.

Explanation:

Given:

Current flowing through each power line, I = 130 A

Distance between the two power lines, d = 40 cm = 0.4 m

Length of power lines, L = 220 m

The force exerted by the power lines on each other is given by the relation:

$F = \frac{\mu_{0}LII }{2\pi d}$

Substitute the suitable values in the above equation.

$F = \frac{4\pi\times10^{-7}\times220\times130\times130 }{2\pi\times0.4}$

F = 1.86 N

Since the direction of current flowing through the power lines are opposite to each other, so the force is attractive in nature. Hence, the direction of force experienced by the power lines on each other is towards the each other.

5 0

3 years ago