answer :
D. 6370.92 m
Explanation:
pls refer to the attachment...
Using the cosine rule (a^2 = b^2 + c^2 - 2bc cos A), we can work out the displacement:
Displacement = a
b = 30
c = 50
A = 180 - 35 = 145 degrees.
a^2= 900 + 2500 -1500*-0.81915...
= 3400 + 1228.728...
= 4628.72...
a = 68.034...
= 68.0m (to 3s.f.).
To work out the angle from starting place, use another configuration of the cosine rule:

:
cos (C)=

= 3028.7.../4080
= 0.7423...
C = 42.069... degrees
= 042 bearing
Answer:
The resistance of A is 6 ohms and the resistance of B is 3 ohms
Explanation:
<u>Step 1:</u> For the first connection (parallel connection), the resistance of B will be calculated.
Note: in a parallel connection, the voltage through each resistor is the same.

<u>Step 2:</u> The resistance of A will be calculated from the second connection (series connection)
Note: in series connection, the current flowing in each resistor is the same

The answer is nodes because nodes stay in a fixed position and i just learnt about this!