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Law Incorporation [45]
4 years ago
12

plz i need help fast................a motion along a straight line with a constant increase in velocity is ?​

Physics
2 answers:
Monica [59]4 years ago
8 0

Answer:

uniform acceleration

Explanation:

The definition for uniform acceleration is:

if an object travels in  a straight line and its velocity increases or decreases by equal amounts in equal intervals of time, then the acceleration is said to be uniform.

Hope this helps.

Good Luck

Effectus [21]4 years ago
5 0

Answer:

Uniform Accleration.

Is the answer.

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Which of these best describes what happens when a ball hits the sweet spot (node) of a bat?
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Answer:

The first option, energy is transferred.

Explanation:

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A bicycle is heading west. It goes 5000m in 500s. What is its velocity?
djverab [1.8K]
The velocity is 10m/s because velocity is calculated by dividing time from displacement so 5000 divided by 500 is 10. 
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_____________ is a process, also known as inlay, in which spaces are cut into wood and filled with wood shapes of a different co
Feliz [49]

Answer:

C. Intarsia

Explanation:

This is a knitting skill that involves different colour patterns. Each color has a yarn for it. However, wood cut in shapes can also be filled with different colour patterns too.

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4 years ago
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A weather balloon, rising vertically at 25.0 m/s, releases an instrument package when it is 100. meters above the ground. How ma
Illusion [34]

Answer:

7.74 seconds

Explanation:

u = 25 m/s

h = - 100 m

Let it takes time t to hit the ground.

Use second equation of motion

h = ut-\frac{1}{2}gt^{2}

-100 = 25t-4.9t^{2}

4.9t^{2}-25t-100=0

t=\frac{25\pm \sqrt{625+4\times 4.9\times 100}}{2\times4.9}

t=\frac{25\pm 50.84}{9.8}

Take positive sign as time can never be negative.

t = 7.74 s

Thus, the package takes 7.74 seconds to reach the ground.

4 0
3 years ago
A truck with a mass of 4285 kg is moving at 9. 35 m/s. it crashes into the rear end of a larger truck with a mass of 5495 kg mov
iogann1982 [59]

(a) The final velocity if the trucks lock together after the collision is 7.66 m/s.

(b) The decrease in the kinetic energy after the collision is 11,165.1 J.

<h3>Conservation of linear momentum</h3>

The final velocity of the two truck system after the collision is determined by applying the principle of conservation of linear momentum as shown below;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

4285(9.35) + 5495(6.35) = v(4285 + 5495)

74,958 = 9,780v

v = 74,958/9780

v = 7.66 m/s

<h3>Initial kinetic energy of the trucks</h3>

K.E = ¹/₂mv²

K.Ei = ¹/₂(4285)(9.35)² + ¹/₂(5495)(6.35)²

K.Ei = 298,088.78 J

<h3>Final kinetic energy of the trucks</h3>

K.Ef = ¹/₂(m₁ + m₂)v²

K.Ef = ¹/₂(4285  + 5495)(7.66)²

K.Ef = 286,923.68 J

<h3>Change in kinetic energy</h3>

ΔK.E = K.Ef - K.Ei

ΔK.E = 286,923.68 J - 298,088.78 J

ΔK.E = - 11,165.1 J

Learn more about linear momentum here: brainly.com/question/7538238

4 0
2 years ago
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