Answer:
v' = -0.0906 m/s
Explanation:
given,
mass of cannon, M = 2240 Kg
mass of the ball, m = 15.5 Kg
speed of cannon ball, v = 131 m/s
speed of he cannon = ?
initial speed of cannon and the cannon ball is equal to 0 m/s
using conservation of energy
(M+m)V = M v' + m v
(M+m) x 0= 22400 v' + 15.5 x 131
22400 v' = -2030.5
v' = -0.0906 m/s
negative sign represent the canon will move in opposite direction of the ball.
hence, speed of cannon is equal to 0.0906 m/s
This is called average speed.Its really simple
Answer:
No
Explanation:
The rate at which solids expand when heated depends on the substance. Metals tend to have higher rates of expansion (per degree change in temperature) than non-metal solids, but there is variation even among metals. A table of expansion coefficients can be found here or here.
Answer:
Control rods
Explanation:
Control rods is unique to nuclear power plants as they are mainly used in nuclear reactors to stabilize the rate of fission of plutonium or uranium. They are usually composed of chemical elements such as cadmium, silver, boron, and indium.
It will take 6.42 s for the ball that is dropped from a height of 206 m to reach the ground.
From the question given above, the following data were obtained:
Height (H) = 206 m
<h3>Time (t) =? </h3>
NOTE: Acceleration due to gravity (g) = 10 m/s²
The time taken for the ball to get to the ground can be obtained as follow:
H = ½gt²
206 = ½ × 10 × t²
206 = 5 × t²
Divide both side by 5
Take the square root of both side
<h3>t = 6.42 s</h3>
Therefore, it will take 6.42 s for the ball to get to the ground.
Learn more: brainly.com/question/24903556
