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mars1129 [50]
3 years ago
15

You are doing x-ray diffraction on a crystal that has a cubic structure, using 0.340-nm x rays. Part A If the lattice spacing is

d = 6.70 × 10−10 m, what is the greatest Bragg angle at which you observe peaks in the intensity of the diffracted rays?
Physics
1 answer:
Mrac [35]3 years ago
6 0

Answer:

∅ = 0.26°

Explanation:

Bragg's law states that:

n×λ = 2×d×sin(∅)

<em>where:</em>

  • <em>d is the lattice spacing.</em>
  • <em>λ is the wavelength of the rays.</em>
  • <em>n is the order of the diffracted rays, n = 1.</em>

then:

sin(∅) = λ/2×d

    ∅ = sin^-1(λ/2×d)

    ∅ = 0.26°

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No. They are different. The bird's distance for that period of time is double the height of the nest above the ground. His displacement for the same time is zero ... the length between the start point and end point.
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Suppose you have two meter sticks, one made of steel and one made of invar (an alloy of iron and nickel), which are the same len
Mekhanik [1.2K]

Answer:

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  • The difference in length for invar is 1.845 x 10⁻⁵ m

Explanation:

Given;

original length of steel, L₁ = 1.00 m

original length of invar, L₁ = 1.00 m

coefficients of volume expansion for steel, \gamma_{st.} =  3.6 × 10⁻⁵ /°C

coefficients of volume expansion for invar, \gamma_{in.} =  2.7 × 10⁻⁶ /°C

temperature rise in both meter stick, θ = 20.5°C

Difference in length, can be calculated as:

L₂ = L₁ (1 + αθ)

L₂  = L₁ + L₁αθ

L₂  - L₁ = L₁αθ

ΔL = L₁αθ

Where;

ΔL is difference in length

α is linear expansivity = \frac{\gamma}{3}

Difference in length, for steel at 20.5°C:

ΔL =  L₁αθ

Given;

L₁ = 1.00 m

θ = 20.5°C

\alpha = \frac{\gamma}{3} = \frac{3.6*10^{-5}}{3} = 1.2*10^{-5} /^oC

ΔL  = 1 x 1.2 x 10⁻⁵ x 20.5 = 2.46 x 10⁻⁴ m

Difference in length, for invar at 20.5°C:

ΔL =  L₁αθ

Given;

L₁ = 1.00 m

θ = 20.5°C

\alpha = \frac{\gamma}{3} = \frac{2.7*10^{-6}}{3} = 0.9*10^{-6}/^oC

ΔL  = 1 x 0.9 x 10⁻⁶ x 20.5 = 1.845 x 10⁻⁵ m

8 0
3 years ago
What is the answer?
Andrews [41]

Answer:

6.26 m/s

Explanation:

Pretty slow.... the PE (Potential Energy) at 2m will be converted to KE (Kinetic Energy) at the bottom of the track (neglecting friction)

PE    =   KE

mgh = 1/2 mv^2     divide both sides of the equation by 'm'

gh    = 1/2 v^2             multiply both sides by 2

2 gh = v^2               take sqrt of both sides

v = sqrt ( 2gh) = sqrt ( 2*9.81*2) = 6.26 m/s

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nadya68 [22]

Answer:

D: It shows that Frida Kahlo used art to cope with her pain.

Explanation:

Within the text given it shows her emotions being lonely, immobile and in pain. But it all shows her asking her father for art which states that art is her sort of relief and happy place.

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The hockey stick hits the puck forward. Give the reaction force
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I think the puck pushes the stick backwards

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