Answer: The force of the engines is 5700N
Explanation:
By the second Newton's law, we have that:
F = m*a
Force equals mass times acceleration.
In this case, we have:
m = 1400kg
a = 3 m/s^2
And the force will be equal to the force of the engines, f, plus the force of the current, -1500 N (because this is pushing you back, so it is in the opposite direction than f), then we have:
F = f - 1500N
Then we have the equation:
f - 1500N = 1400kg*3m/s^2 = 4200N
f - 1500N = 4200N
f = 4200N + 1500N = 5700N
The force of the engines is 5700N
Your answer is <span>Isaac Newton. Hope this helps.</span>
Answer:
120 is the correct answer
<span>The life forms of the biosphere are located within Earth's surface.</span>
Answer:
The total work done by the two tugboats on the supertanker is 3.44 *10^9 J
Explanation:
The force by the tugboats acting on the supertanker is constant and the displacement of the supertanker is along a straight line.
The angle between the 2 forces and displacement is ∅ = 15°.
First we have to calculate the work done by the individual force and then we can calculate the total work.
The work done on a particle by a constant force F during a straight line displacement s is given by following formula:
W = F*s
W = F*s*cos∅
With ∅ = the angles between F and s
The magnitude of the force acting on the supertanker is F of tugboat1 = F of tugboat 2 = F = 2.2 * 10^6 N
The total work done can be calculated as followed:
Wtotal = Ftugboat1 s * cos ∅1 + Ftugboat2 s* cos ∅2
Wtotal = 2Fs*cos∅
Wtotal = 2*2.2*10^6 N * 0.81 *10³ m s *cos15°
Wtotal = 3.44*10^9 Nm = <u>3.44 *10^9 J</u>
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The total work done by the two tugboats on the supertanker is 3.44 *10^9 J
