Given the mass of R-134a m = 300kg; Volume of the container V = 9 cu. meter; Temperature of R-134a T = 10 degrees Celsius;
Formula of specific volume : v = V / m = 9 / 300 = 0.03 cu. m / kg.
At T = 10 degrees Celsius from saturated R-134a tables, vf = 0.0007930 cu. m /kg; vg = 0.049403 cu. m/kg. We know v = vf + x (vg - vf), so 0.03 = 0.0007930 + x (0.049403 - 0.0007930), which makes x = 0.601.
Specific enthalpy of R-134a in the container is h = hf + x*hfg = 65.43 + (0.601 * 190.73). Answer is 180.0587 kJ/kg
Answer:
Explanation:
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Answer:
The power of the kettle is P = 1 watt.
Explanation:
The definition of power is:
Power equals the quotient between work and time, or:
P = w/t.
In this case, we know that the work is:
w = 1J
And the time is:
t = 1 s
Then the power will be:
P = 1J/1s = 1 J/s
Also knowing that:
1 J/s = 1 W
(w is the unit for Watt)
We can conclude that the power of the kettle is:
P = 1 W