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zhuklara [117]
3 years ago
11

You wiggle a string, that is fixed to a wall at the other end, creating a sinusoidal wave with a frequency of 2.00 Hz and an amp

litude of 0.075 m. The speed of the wave is 12.0 m/s. At t=0 the string has a maximum displacement and is instantaneously at rest. Assume no waves bounce back from the far end of the wall. Find the angular frequency, period, wavelength, and wave number. Write a wave function describing the wave. Write equations for the displacement, as a function of time, of the end of the string that is being wiggled and at a point 3.00 m from that end. Determine the speed of the medium and draw history and snapshot graphs for the waves created.
Physics
1 answer:
allochka39001 [22]3 years ago
4 0

Answer:hhhkkzkxixuhhhdhhdhdhhhdhhhshsbbsbzhhdhhdhhhshhhdhhdusudhggdydyydhshdhgddhsjsudhdhhdh

Explanation:NzjzjhbxxhzhdghsjshshhHjajskajakakakakaiaiaiijhayayayagayahahah

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Newton's motion laws state that if an object is at rest or in movement, it will tend to maintain its basal state.

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These laws explain why objects in movement tend to maintain the same velocity for a short period of time.

In conclusion, Newton's motion laws state that if an object is at rest or in movement, it will tend to maintain its basal state.

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Witch of the following is not an appropriate unit for power
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In physics grade 10 number 8 in the pic how do we do it thanks in advance
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3 years ago
Two spectators at a soccer game in Montjuic Stadium see, and a moment later hear, the ball being kicked on the playing field. Th
Akimi4 [234]

Answer:

a) The distance of spectator A to the player is 79.2 m

b) The distance of spectator B to the player is 43.9 m

c) The distance between the two spectators is 90.6 m

Explanation:

a) Knowing the time it takes the sound to reach both spectators, we can calculate their position relative to the player, using this equation:

x = v * t

where:

x = position of the spectators

v = speed of sound

t = time

Then, the position for spectator A relative to the player is:

x = 343 m/s * 0.231 s = 79.2 m

b)For spectator B:

x = 343 m/s * 0.128 s

x = 43.9 m

The distance of spectator A and B to the player is 79.2 m and 43.9 m respectively.

c) To calculate the distance between the spectators, please see the attached figure. Notice that the distance between the spectators is the hypotenuse of the triangle formed by the sightline of both. We already know the longitude of the two sides. Then, using Pythagoras theorem:

(Distance AB)² = A² + B²

(Distance AB)² = (79.2 m)² + (43.9 m)²

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6 0
3 years ago
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