What do astronomers call a system that is composed of more than two stars

Two large conducting parallel plates A and B are separated by 2.4 m. A uniform field of 1500 V/m, in the positive x-direction, i

Lapatulllka [165]

Answer:

a. 1.027 x 10^7 m/s b. 3600 V c. 0 V and d. 1.08 MeV

Explanation:

a. KE =1/2 (MV^2) where the M is mass of electron

b. E = V/d

c. V= 0 V (momentarily the pd changes to zero)

d KE= 300*3600 v = 1.08 MeV

6 0

3 years ago

Driving on asphalt roads entails very little rolling resistance, so most of the energy of the engine goes to overcoming air resi

Bad White [126]

A) Agreed.
b) Value agreed but units should be W (watts). 

c) Here's one method... 

15 miles = 24140 m 

1 gallon of gasoline contains 1.4×10⁸ J. 

So moving a distance of 24140m requires gasoline containing 1.4×10⁸ J 

Therefore moving a distance of 1m requires gasoline containing 1.4×10⁸/24140 = 5800 J 

Overcoming rolling resitance for 1m requires (useful) work = force x distance = 1000x1 = 1000J 

So 5800J (in the gasoline) provides 1000J (overcoming rolling resistance) of useful work for each metre moved. 

Efficiency = useful work/total energy supplied 
= 1000/5800 
= 0.17 (=17%)

8 0

3 years ago

A particle moves in a straight line with the velocity function v ( t ) = sin ( w t ) cos 3 ( w t ) . find its position function

Sunny_sXe [5.5K]

Integrating the velocity equation, we will see that the position equation is:

$$f(t)=\frac{\cos ^3(\omega t)-1}{3}$

<h3>How to get the position equation of the particle?</h3>

Let the velocity of the particle is:

$$v(t)=\sin (\omega t) * \cos ^2(\omega t)$

To get the position equation we just need to integrate the above equation:

$$f(t)=\int \sin (\omega t) * \cos ^2(\omega t) d t$

$$\mathrm{u}=\cos (\omega \mathrm{t})$

Then:

$$d u=-\sin (\omega t) d t$

$\Rightarrow d t=-d u / \sin (\omega t)$

Replacing that in our integral we get:

$\int \sin (\omega t) * \cos ^2(\omega t) d t$

$-\int \frac{\sin (\omega t) * u^2 d u}{\sin (\omega t)}-\int u^2 d t=-\frac{u^3}{3}+c$

Where C is a constant of integration.

Now we remember that $u=\cos (\omega t)$

Then we have:

$$f(t)=\frac{\cos ^3(\omega t)}{3}+C$

To find the value of C, we use the fact that f(0) = 0.

$$f(t)=\frac{\cos ^3(\omega * 0)}{3}+C=\frac{1}{3}+C=0$

C = -1 / 3

Then the position function is:

$$f(t)=\frac{\cos ^3(\omega t)-1}{3}$

Integrating the velocity equation, we will see that the position equation is:

$$f(t)=\frac{\cos ^3(\omega t)-1}{3}$

To learn more about motion equations, refer to:

brainly.com/question/19365526

#SPJ4

4 0

1 year ago

What causes earthquakes,tsunami, and volcanic eruptions to happen certain places and not others

Dafna11 [192]

These are all caused by tectonic plate movements. Some areas of the globe are more susceptible to these disasters because they are on or near a fault line where the Earth’s tectonic plates rub against one another, slip beside and under each other, or collide. The places near fault lines are more likely to see earthquakes, tsunamis, and volcanic activity.

5 0

3 years ago

Whoever gets this right gets brainlyess answer and it's worth 10 points :)

Gelneren [198K]

A is only the area of one tile. It wants the area of the whole floor.
area of parallelogram is b*h=0.952. There are 9500 of them so 0.952*9500=904.4 (answer c)

5 0

3 years ago