Question

Determine the [OH⁻] concentration in a 0.344 M Ca(OH)₂ solution.

Answer 1

Answer:

$0.688M$

Explanation:

Hello,

In this case, it is widely acknowledged that strong bases usually correspond to those formed with metals in groups IA and IIA which have relatively high activity and reactivity, therefore, when they are dissolved in water the following dissociation reaction occurs (for calcium hydroxide):

$Ca(OH)_2\rightarrow Ca^{2+}+2OH^-$

In such a way, for the same volume, we can compute the concentration of hydroxyl ions by simple stoichiometry (1:2 molar ratio):

$0.344\frac{molCa(OH)_2}{L}*\frac{2molOH^-}{1molCa(OH)_2} \\\\0.688\frac{mol OH^-}{L}$

Or simply:

$0.688M$

Regards.