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3 years ago

Determine the [OH⁻] concentration in a 0.344 M Ca(OH)₂ solution.

Chemistry

1 answer:

slavikrds [6]3 years ago

8 0

Answer:

$0.688M$

Explanation:

Hello,

In this case, it is widely acknowledged that strong bases usually correspond to those formed with metals in groups IA and IIA which have relatively high activity and reactivity, therefore, when they are dissolved in water the following dissociation reaction occurs (for calcium hydroxide):

$Ca(OH)_2\rightarrow Ca^{2+}+2OH^-$

In such a way, for the same volume, we can compute the concentration of hydroxyl ions by simple stoichiometry (1:2 molar ratio):

$0.344\frac{molCa(OH)_2}{L}*\frac{2molOH^-}{1molCa(OH)_2} \\\\0.688\frac{mol OH^-}{L}$

Or simply:

$0.688M$

Regards.

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As the molecules approach, their electron clouds repel, so energy is required for the collision to occur and therefore the reaction. The activation energy comes from the heat of the system, that is, the translational, vibrational energy, etc. of each molecule. However, if this energy is not enough, the reaction will not be spontaneous.

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