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sveticcg [70]
4 years ago
15

Can anyone help me please.

Mathematics
1 answer:
EleoNora [17]4 years ago
8 0
2x +9 <0

x > -12

2x<-9

2x<-9/2  (9/2 = 4.5)


x >-12
 the answer is all integers between -12 and -4.5

-11, -10, -9, -8, -7, -6, -5

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sveticcg [70]
It will hit the ground after 3.499 seconds.

To solve this you first have to find the value of h(0) in this equation. That is the height from which it was dropped.

You can input any of the points into the equation and solve for the missing part. You will get 60 for the height.

The use the quadratic formula to see that it reaches the ground after 3.499 seconds.
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3 years ago
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Hoy Many times as great as 10% is 100% answer
Evgesh-ka [11]

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8 0
4 years ago
Using Cramer’s Rule, what is the value of y in the system of linear equations below?
Vadim26 [7]

for the system of equations

a_1x+b_1y=c_1 \\a_2x+b_2y=c_2

the three matrices needed to use Cramer's Rule are:

D=\left[\begin{array}{cc}a_1&b_1\\a_2&b_2\end{array}\right] \\\\D_x=\left[\begin{array}{cc}c_1&b_1\\c_2&b_2\end{array}\right] \\\\D_y=\left[\begin{array}{cc}a_1&c_1\\a_2&c_2\end{array}\right].

To use Cramer's Rule we have to calculate the three determinants listed below of the matrices listed below.

D=\left[\begin{array}{cc}2&5\\-3&-2\end{array}\right] \\\\D_x=\left[\begin{array}{cc}-13&5\\3&-2\end{array}\right] \\\\D_y=\left[\begin{array}{cc}2&-13\\-3&3\end{array}\right] .

The value of the determinants are shown below.

det(D)=(2)(-2)-(-3)(5)=-4+15=11\\det(D_x)=(-13)(-2)-(3)(5)=26-15=11\\det(D_y)=(2)(3)-(-3)(-13)=6-39=-33\\

The value of y is \frac{det(D_y)}{det(D)}=-\frac{33}{11} =-3..

3 0
4 years ago
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Answer:36.36%

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%change=100 X (final-inital value) divided by initial

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