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Evgesh-ka [11]
2 years ago
5

Use this system of equations to answer the questions

Mathematics
2 answers:
poizon [28]2 years ago
7 0

Answer:

the first one is 2 the second one is 3

Step-by-step explanation:

Over [174]2 years ago
6 0

Answer:

1. To eliminate x-term, multiply the second by -2

2. To eliminate y-term, multiply the second by 3

Step-by-step explanation:

4x - 9y = 7 (1)

-2x + 3y = 4 (2)

1. To eliminate x-term, multiply the second by -2

-2x + 3y = 4 (2) × 2

-4x + 6y = 8 (3)

4x - 9y = 7 (1)

Add (3) and (1)

6y - 9y = 8 + 7

-3y = 15

y = 15/-3

y = -5

4x - 9y = 7 (1)

4x - 9(-5) = 7

4x + 45 = 7

4x = 7 - 45

4x = -38

x = -38/4

x = -9.5

4x - 9y = 7 (1)

-2x + 3y = 4 (2)

2. To eliminate y-term, multiply the second by 3

-2x + 3y = 4 (2) × 3

-6x + 9y = 12 (3)

4x - 9y = 7 (1)

-6x + 4x = 12 + 7

-2x = 19

x = 19/-2

x = -9.5

4x - 9y = 7 (1)

4(-9.5) - 9y = 7

-38 - 9y = 7

-38 - 7 = 9y

-45 = 9y

y = -45/9

y = -5

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For a medical study, a researcher wishes to select people in the middle 60% of the population based on blood pressure.
Finger [1]

Answer:

Lower limit: 113.28

Upper limit: 126.72

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 120, \sigma = 8

Middle 60%

So it goes from X when Z has a pvalue of 0.5 - 0.6/2 = 0.2 to X when Z has a pvalue of 0.5 + 0.6/2 = 0.8

Lower limit

X when Z has a pvalue of 0.20. So X when Z = -0.84

Z = \frac{X - \mu}{\sigma}

-0.84 = \frac{X - 120}{8}

X - 120 = -0.84*8

X = 113.28

Upper limit

X when Z has a pvalue of 0.80. So X when Z = 0.84

Z = \frac{X - \mu}{\sigma}

0.84 = \frac{X - 120}{8}

X - 120 = 0.84*8

X = 126.72

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