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riadik2000 [5.3K]
3 years ago
6

How does the atmospheric pressure vary with height?

Chemistry
2 answers:
Aleksandr [31]3 years ago
7 0
Pressure decreases with increasing altitude
Anna71 [15]3 years ago
4 0
Atmospheric pressure decreases with increasing height

Hope this helps!
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Egg white, marshmallow, and smoke from a smokestack are examples of _____. suspensions colloids solutions
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They are an example of colloids .....


6 0
3 years ago
Can you balance 12 blocks on the 3x2 platform
Jobisdone [24]
Yes, it is possible to go do because it would be 2 stacks of 6
3 0
2 years ago
0.53g of acetanilide was subjected to kjeldahl determination and the ammonia produced was collected in 50cm3 of 0.50M of h2so4.o
Lady bird [3.3K]

Answer:

10.57% of N in acetanilide

Explanation:

All nitrogen in the sample is converted in NH₃ in the Kjeldahl determination. The NH₃ reacts with H₂SO₄ as follows:

2NH₃ + H₂SO₄ → 2NH₄⁺ + SO₄²⁻

The acid in excess in titrated with Na₂CO₃ as follows:

Na₂CO₃ + H₂SO₄ → Na₂SO₄ + H₂O + CO₂

To solve this question we must find the moles of sodium carbonate = Moles of H₂SO₄ in excess. The added moles - Moles in excess = Moles of sulfuric acid that reacts:

<em>Moles Na₂CO₃ anf Moles H₂SO₄ in excess:</em>

0.025L * (0.05mol / L) = 1.25x10⁻³ moles Na₂CO₃ / 0.01360L =

0.09191M * 0.250L = 0.0230 moles H₂SO₄ in excess.

<em>Moles H₂SO₄ added:</em>

0.050L * (0.50mol / L) = 0.0250 moles H₂SO₄ added

<em>Moles that react:</em>

0.0250 moles - 0.0230 moles = 0.0020 moles H₂SO₄

<em>Moles of NH₃ = Moles N:</em>

0.0020 moles H₂SO₄ * (2mol NH₃ / 1mol H₂SO₄) = 0.0040 moles NH₃ = Moles N

<em>mass N and mass percent:</em>

0.0040 moles N * (14g / mol) = 0.056gN / 0.53g * 100 =

<h3>10.57% of N in acetanilide</h3>
7 0
2 years ago
Hydrogenation reactions, in which H2 and an "unsaturated" organic compound combine, are used in the food, fuel, and polymer indu
ddd [48]

<u>Answer:</u> The amount of heat released is 56 MJ.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}  

Given mass of C_2H_6 = 12 kg = 12000 g    (Conversion factor: 1 kg = 1000 g)

Molar mass of C_2H_6 = 30 g/mol

Putting values in above equation, we get:

\text{Moles of }C_2H_6=\frac{12000g}{30g/mol}=400mol

The chemical reaction for hydrogenation of ethene follows the equation:

C_2H_4+H_2\rightarrow C_2H_6

By Stoichiometry of the reaction:

When 1 mole of ethane releases 140 kJ of heat.

So, 400 moles of ethane will release = \frac{140}{1}\times 400=56000kJ of heat.

Converting this into Mega joules, using the conversion factor:

1 MJ = 1000 kJ

So, \Rightarrow 56000kJ\times (\frac{1MJ}{1000kJ})=56MJ

Hence, the amount of heat released is 56 MJ.

8 0
3 years ago
Which coefficients balance the following equation?
Nookie1986 [14]
Answer: A
FeCl3 + 3 NaOH -> Fe(OH)3 + 3 NaCl
7 0
3 years ago
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