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sashaice [31]
3 years ago
6

Butane gas reacts with oxygen gas to give carbon dioxide gas and water vapor (gas). If you mix butane and oxygen in the correct

stoichiometric ratio, and if the total pressure of the mixture is 392 mmHg, what is the pressure (in mmHg) of water vapor after the reaction has completed (temperature and volume do not change).
Chemistry
1 answer:
Fittoniya [83]3 years ago
7 0

Answer:

118.776 mmHg

Explanation:

The equation of the reaction is;

C4H10(g) + 13/2 O2(g) ------> 4CO2(g) + 5H20(g)

Now the mole ratio  according to the balanced reaction equation is;

1 : 6.5 : 4 : 5

Hence, the total number of moles present = 1 + 6.5 + 4 + 5 = 16.5 moles

Mole fraction of water vapour = 5/16.5 = 0.303

We also know that;

Partial pressure= mole fraction * total pressure

Partial pressure of H20(g) = 0.303 *  392 mmHg = 118.776 mmHg

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7

Explanation:

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How did coroners handle their responsibilities in the early 1900s? Why was there a need for significant change in the job?
Lorico [155]

Answer:

In the twentieth century, criminologists and forensics strive to summarize the preceding discoveries. In different countries tendencies are beginning to manifest that increase the field of criminological activity in different branches such as criminalistics in Germany; others, penology; and others like the United States, weighed the study as a whole of the science of crime and the science of social reaction provoked by it. In this century, criminology and forensic science had a notable influence on the evolution of criminal law.

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3 0
3 years ago
What volume of water is required to prepare 0.1 M H3PO4 from 100 ml of 0.5 M solution?
ExtremeBDS [4]

Answer: A volume of 500 mL water is required to prepare 0.1 M H_{3}PO_{4} from 100 ml of 0.5 M solution.

Explanation:

Given: M_{1} = 0.1 M,    V_{1} = ?

M_{2} = 0.5 M,       V_{2} = 100 mL

Formula used to calculate the volume of water is as follows.

M_{1}V_{1} = M_{2}V_{2}

Substitute the values into above formula as follows.

M_{1}V_{1} = M_{2}V_{2}\\0.1 M \times V_{1} = 0.5 M \times 100 mL\\V_{1} = 500 mL

Thus, we can conclude that a volume of 500 mL water is required to prepare 0.1 M H_{3}PO_{4} from 100 ml of 0.5 M solution.

7 0
3 years ago
There are three naturally occurring isotopes of the hypothetical element hilarium 45Hi, 46Hi, and 48Hi. The percentages of these
den301095 [7]

Answer:

46.761g/mol

Explanation:

Given parameters:

Element = Hilarium , Hi

Isotopes: Hi- 45, Hi-46 and Hi- 48

Natural abundance of Hi-45 = 18.3%

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                                     Hi-48 = 47.2%

Unknown:

Atomic weight of naturally occurring Hilarium = ?

Solution:

Isotopes have been studied extensively by mass spectrometry. The method is used to determine the proportion/percentage/fraction by which each of the isotopes of an element occurs in nature. The proportion is called geonormal abundance. From this we can calculate the atomic weight of an element.

 We can use the expression below to find this value:

       Atomic weight = m₄₅α₄₅ + m₄₆α₄₆ + m₄₈α₄₈

    m is the atomic mass of each isotope and α is the abundance

Atomic weight = (45 x \frac{18.3}{100} ) + (46 x  \frac{34.5}{100} ) + (48 x  \frac{47.2}{100})

Atomic weight of Hi = 8.235 + 15.870 +  22.656 = 46.761g/mol

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Answer:

The table is preventing the book from accelerating downwards.

Explanation:

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