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creativ13 [48]
4 years ago
8

Ann believes that carbohydrates store more energy than lipids. Nicco believes that lipids store twice as much energy as carbohyd

rates. Who is correct?
Chemistry
2 answers:
mash [69]4 years ago
4 0
Out of all the choices, Nicco is correct.
mojhsa [17]4 years ago
4 0

Answer: Nicco is correct

Explanation:  Carbohydrate and Lipids are both involved in the process of the storage of the energy but carbohydrate stores energy for short time and lipids store it for a long term.

Lipids do store twice as much energy as carbohydrates because the energy per gram value in case of lipids is higher than that of carbohydrates.

Thus nicco's belief is correct regarding the storage of energy which is higher in lipids than carbohydrates.

You might be interested in
2. Nitrogen has two naturally occurring
kvv77 [185]

Answer:

Suppose that:

Mass of N-14= 14

and Mass of N-15= 15

fraction N-14 x 14 + fraction N-15 x 15 = 14.007

now.. if the fractions were =, that is if fraction N-14 = fraction N-15 = 0.5, then...

0.5 x 14 + 0.5 x 15 = 14.5

more N-15 would make that number larger...

0.3 x 14 + 0.7 x 15 = 14.7

let x = abundance of N-14, then (1-x) = abundance of N-15, and we could solve for x.

(X)x14 + (1-X)x 15 = 14.007

14X + 15 - 15X = 14.007

X = 0.993

the relative abundance of N-14 = 99.3%

the relative abundance of N-15 = 0.7%

So, according to the above explanation N-14 is abundant

Explanation:

Suppose that:

Mass of N-14= 14

and Mass of N-15= 15

fraction N-14 x 14 + fraction N-15 x 15 = 14.007

now.. if the fractions were =, that is if fraction N-14 = fraction N-15 = 0.5, then...

0.5 x 14 + 0.5 x 15 = 14.5

more N-15 would make that number larger...

0.3 x 14 + 0.7 x 15 = 14.7

let x = abundance of N-14, then (1-x) = abundance of N-15, and we could solve for x.

(X)x14 + (1-X)x 15 = 14.007

14X + 15 - 15X = 14.007

X = 0.993

the relative abundance of N-14 = 99.3%

the relative abundance of N-15 = 0.7%

So, according to the above explanation N-14 is abundant

8 0
3 years ago
Which of the following is an accurate statement
Yanka [14]
What are the statements?
8 0
3 years ago
How many valence electrons does Carbonic Acid contain?
geniusboy [140]
4 carbon electrons. Hope this helps have a nice day
6 0
3 years ago
Methylcyclopentene reacting with reacting with sulfuric acid and water
dlinn [17]

Answer:

The product is 1-methylcyclopentanol  

Explanation:

The acid-catalyzed hydration of alkenes involves the addition of a water molecule to a C=C double bond.

H₂O + C=C ⟶ H-C-C-OH

An H atom adds to one of the C atoms, and an OH group adds to the other

This reaction follows Markovnikov’s rule — the H adds to the C atom that has more hydrogen atoms, and the OH adds to the more substituted carbon.

The steps of the mechanism are:

  1. The aqueous sulfuric acid generates hydronium ions
  2. The nucleophilic π electrons attack an H atom  on the hydronium ion, forming a carbocation on the more substituted C atom.
  3. The lone pair electrons on a water molecule attack the carbocation , forming an oxonium ion.
  4. Another water molecule removes the extra proton.

The product is the alcohol with the OH group on the more substituted carbon — 1-methylcyclopentanol.

7 0
4 years ago
A student mixed 50 ml of 1.0 M HCl and 50 ml of 1.0 M NaOH in a coffee cup calorimeter and calculated the molar enthalpy change
MrRa [10]

Answer:

-54 kJ/mol

Explanation:

Given that:

A student mixed 50 ml of 1.0 M HCl and 50 ml of 1.0 M NaOH in a coffee cup calorimeter and calculated the molar enthalpy change of the acid-base neutralization reaction to be –54 kJ/mol

i.e

50 ml of 1.0 M HCl +  50 ml of 1.0 M NaOH -----> -54 kJ/mol

If he repeat the same experiment with :

100 ml of 1.0 M HCl + 100 ml of 1.0 M NaOH. ------> ????

From The experiment; the molar enthalpy of change of the acid-base neutralization reaction will be -54 kJ/mol

This is because : The second reaction requires 50 ml in order to neutralize the reaction, then the remaining 50 ml will be excess, Hence, there is no change in the enthalpy of the reaction.

Similarly; we can assume that :

In the first reaction;  P moles of  is used to liberate Q kJ heat ; then  the change in molar enthalpy will be Q/P (kJ/mol).

SO; when he used 100 ml ;

then the amount of moles used is double, likewise the heat liberated will be doubled ;

So;

2P moles is used to liberate 2Q kJ heat ;

2P/2Q = Q/P ( kJ/mol) = -54 kJ/mol

8 0
3 years ago
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