A sealed container contains 0.10 moles of nitrogen gas and 0.20 moles of oxygen gas. If Temperature of the mixture is constant,
2 answers:
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Answer:
a) 2.01 g
Explanation:
- Na₂CO₃ (s) + 2AgNO₃ (aq) → Ag₂CO₃ (s) + 2NaNO₃
First we <u>convert 0.0302 mol AgNO₃ to Na₂CO₃ moles</u>, in order to <em>calculate how many Na₂CO₃ moles reacted</em>:
- 0.0302 mol AgNO₃ *
= 0.0151 mol Na₂CO₃
So the remaining Na₂CO₃ moles are:
- 0.0340 - 0.0151 = 0.0189 moles Na₂CO₃
Finally we <u>convert Na₂CO₃ moles into grams</u>, using its <em>molar mass</em>:
- 0.0189 moles Na₂CO₃ * 106 g/mol = 2.003 g Na₂CO₃
The closest answer is option a).
You must first calculate the total weight of 1 mole of the substance. You do this by finding the molar weights on the periodic table of each of the elements in the compound:
So now we take the amount of each element that is given in the compound and divide it by the total mass of the compound:
Carbon: 96.08g
Carbon = 49.48%
Nitrogen: 56.028g
Nitrogen = 28.85%
Oxygen: 31.998g
Oxygen = 16.48%