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NISA [10]
3 years ago
12

What are some visible signs of an acid-base reaction?

Chemistry
1 answer:
marta [7]3 years ago
6 0
I think one of the signs is <span>water and  salt are formed 

</span>
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A 50 L cylinder is filled with argon gas to a pressure of 10130.0 kPa at 300°C. How many moles of argon gas does the cylinder co
Vlad1618 [11]
To answer this question, we will use the general gas law which states that:
PV = nRT where:
P is the pressure of the gas = <span>10130.0 kPa
</span>V is the volume of the gas = 50 liters
n is the number of moles that we want to calculate
R is the gas constant = <span>8.314 L∙kPa/K∙mol
T is the temperature = 300+273 = 573 degree kelvin

Substitute with the givens in the equation to get the number of moles as follows:
</span><span>10130 * 50 = n * 8.314 * 573
506500 = 4763.922 n
n = </span>506500 / 4763.922
n = 106.3199 moles
7 0
4 years ago
How many molecules are in 1.95 moles of water?
OLEGan [10]
Water has a molar mass of 18.015 g/mol . This means that one mole of water molecules has a mass of 18.015 g . So, to sum this up, 6.022⋅1023 molecules<span> of water will amount to 1 mole of water, which in turn will have a mass of 18.015 g . 2.7144moles H2O ⋅</span>6.022<span>⋅1023molec.1mole H2O =1.635⋅1024molec.</span>
3 0
3 years ago
Read 2 more answers
Solve for V2 when P1 = 1.0 atm V1 = 22.4 L and P2 = 4.0 atm <br> This is a Boyle’s law gas problem
morpeh [17]
P1/V1=P2/V2
1/22.4=4/x
X=4 multiple by 22.4
V2=89.6L
3 0
3 years ago
In the reaction 4Al+3O2→_Al2O3 , what coefficient should be placed in front of the Al2 to balance the reaction?
nika2105 [10]

Sorry I came a lil late,

The answer to your question is, 2.

Hope this helps! :)

6 0
3 years ago
Read 2 more answers
3. Explain the relationship between power, energy and time.
likoan [24]
There is a very simple relationship between the three. First off, power is the amount of energy used over a certain amount of time. Energy is the capacity of carrying out that power. Lastly, time depends on how much energy you have to exert the work.

Hope this helps :)
7 0
3 years ago
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