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Len [333]
3 years ago
7

In a stack of undisturbed rock layers, the upper layers are younger than the lower layers. This is also stated as the law of ___

__.
Chemistry
2 answers:
Ilia_Sergeevich [38]3 years ago
5 0

Answer:

The answer is: Law of superposition

Explanation:

In geochronology, the law of superposition is a fundamental principle given by the Danish scientist Nicolas Steno.

According to this law, in an undisturbed stratigraphic sequence,<u> the youngest strata is always found on the top of the sequence,</u> and the layers present below get progressively older as we go from the top to the bottom of the sequence. Thus, <u>the oldest strata is found at the bottom of the stratigraphic sequence.</u>

zvonat [6]3 years ago
3 0
The anwer is The Law of Superposition
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JulsSmile [24]

Answer:

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Explanation:

6 0
2 years ago
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Use the unbalanced equation NH3 + O2 = NO + H2O
Elodia [21]
<span>The balance format is
4NH3+ 5O2 -------> 4NO + 6H2O </span>
7 0
3 years ago
How mamy moles of NaCl will be produced from 83.0g of Na, assuming Cl2 is available in excess
Anestetic [448]

Answer:

3.62moles

Explanation:

First let us generate a balanced equation for the reaction

2Na + Cl2 —> 2NaCl

Molar Mass of Na = 23g/mol

Mass of Na from the balanced equation = 2 x 23 = 46g

Molar Mass of NaCl = 23 + 35.5 = 58.5g/mol

Mass of NaCl from the balanced equation = 2 x 58.5 = 117g

From the question,

46g of Na produced 117g of NaCl.

Therefore, 83g of Na will produce = (83 x 117)/46 = 211.11g of NaCl

Converting this mass (211.11g of NaCl) to mole, we obtain:

n = Mass /Molar Mass

n = 211.11/ 58.5

3.62moles

8 0
3 years ago
What happened to the amplitude from wave A to wave B?
DanielleElmas [232]
A. <span>The amplitude doubled hope this helps and have a nice day</span>
5 0
3 years ago
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Please help me, I really don't want to fail but I don't know how to do this
Brrunno [24]

Answer:

A)

<u>4, 7, 4, 6</u>

B)

<u>12 moles</u>

Explanation:

NH_{3}(g) + O_{2}(g) \: → NO_{2} + H_{2}O(g)

__↑______↑

8.00 mol | 14.00 mol

________________

NH_{3}(g) + O_{2}(g) \: → NO_{2} + H_{2}O(g)

You can turn this into a system of variables which are solvable.

To do this, create variables for the coefficients of each compound in the reaction respectively.

a(NH_{3}(g)) + b(O_{2}(g)) → \\c(NO_{2}) + d(H_{2}O(g))

Because to be balanced, the count of atoms in each element of the compound correspond to the coefficient of the variable in that compound so that the count of the left (reactant) side is set equal to the right (product) side.

a corresponds to the coefficient of the first compound, b corresponds to the coefficient of the second compound, c corresponds to the coefficient of the third compound, and d corresponds to the coefficient of the fourth compound.

(Reactant = Product)

Reactant: 1a [N] Product: 1c.

Reactant: 3a [H] Product: 2d.

Reactant: 2b [O] Product: 2c + 1d.

Thus the system is:

1a = 1c

3a = 2d

2b = 2c + 1d.

Then just use the substitution methods to solve.

3 0
2 years ago
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